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Sonja [21]
3 years ago
7

Courtney biked 8 laps around a park. The app on her phone showed she biked 11.12 miles. What is the constant of proportionality

that relates the distance, y, to the number of laps, x?
Mathematics
1 answer:
Ad libitum [116K]3 years ago
7 0

Answer:

1.39/1

Step-by-step explanation:

the answer can be explained by dividing the distance covered by thebiker to the number of laps covered by the same. This gives us the ratio of distance per unti lap for the biker.

11.12 miles divided by 8 gives us=  1.39

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Dedi had a combination lock.To open the lock he started at 37.He made 3 half turns clockwise and 3 quarter turns anticlockwise
Lerok [7]
Turning clockwise means the number increase, and counterclockwise means the number decreases

Therefore your answer is 37 + (3*1/2)-(3*1/4)

= 37.75

Hope this helped :)
5 0
2 years ago
RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly
tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

4 0
3 years ago
Solve each equation using the symbolic method. X4+2=26
Jlenok [28]
Hope this helps you out

3 0
3 years ago
For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
Does anybody know this answer?
creativ13 [48]

Answer:

circumference=2πr

=2×3.14×8.5

=53.38cm

7 0
2 years ago
Read 2 more answers
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