The answer is probably -78*degree sign*C.
Answer: The equation is y = 0.25/(x - 4) + 3
Step-by-step explanation:
If we have a function y = f(x)
A compression means that we multiply the function by a factor smaller than 1.
Then the vertical compression by a factor of 0.25 is:
y = 0.25*f(x)
a translation by A units to the right, means that we need to valuate the function in x - A.
So now we have:
y = 0.25*f(x - 4)
A translation in the y-axis means that we need to add a constant to the equation, then if we tralate it by 3 units up, we have:
y = 0.25*f(x - A) + 3
Then, if f(x) = 1/x
Our new equation is:
y = 0.25/(x - 4) + 3
Answer:
The statements describe transformations performed in f(x) to create g(x) are:
a translation of 5 units up ⇒ c
a vertical stretch with a scale factor of 2 ⇒ d
Step-by-step explanation:
- If f(x) stretched vertically by a scale factor m, then its image g(x) = m·f(x)
- If f(x) translated vertically k units, then its image h(x) = f(x) + k
Let us use these rule to solve the question
∵ f(x) = x²
∵ g(x) is created from f(x) by some transformation
∵ g(x) = 2x² + 5
→ Substitute x² by f(x) in g(x)
∴ g(x) = 2f(x) + 5
→ Compare it with the rules above
∴ m = 2 and k = 5
→ That means f(x) is stretched vertically and translated up
∴ f(x) is stretched vertically by scal factor 2
∴ f(x) is translated 5 uints up
The statements describe transformations performed in f(x) to create g(x) are:
- a translation of 5 units up
- a vertical stretch with a scale factor of 2
Answer:
Step-by-step explanation:
We are given the following in the question:
The needle size should not be too big and too small.
The diameter of the needle should be 1.65 mm.
We design the null and the alternate hypothesis
Sample size, n = 35
Sample mean, 
= 1.64 mm
Sample standard deviation, s = 0.07 mm
Type I error:
- It is the error of rejecting the null hypothesis when it is true.
- It is also known as false positive error.
- It is the rejecting of a true null hypothesis.
Thus, type I error in this study would mean we reject the null hypothesis that the average diameter is 1.65 mm but actually the average diameters of the needle is 1.65 mm.
Thus, average diameter is 1.65 mm and we decide that it is not 1.65 mm.
.0514006682 is the answer
