All categories

3 years ago

For the inverse variation equation xy = k, what is the constant of variation, k, when x = 7 and y = 3? 3/7 7/3 10 21

Mathematics

2 answers:

Paha777 [63]3 years ago

8 0

Option D! which would be 21!

Elza [17]3 years ago

4 0

Hello there,

So by using the formula xy=k just plug in both x and y.

So this would be (7)(3)=k

Which means 21=k

Hope this helped!

You might be interested in

Jana is training for a triathlon. If Jana biked at a constant rate, how many miles did she bike in the first 15 minutes?

Harman [31]

In order to answer, I would first need to know Jana's speed, not that she biked at a constant rate.

7 0

3 years ago

What is the ordered pair solution for y>= 1/3x+4

blondinia [14]

Answer:

Step-by-step explanation:

y > (1/3)x + 4 has an infinite number of solutions. Draw a dashed line representing y = (1/3)x + 4 and then pick points at random on either side of this line. For example, pick (1, 6). Substitute 1 for x in y > (1/3)x + 4 and 6 for y. Is the resulting inequality true? Is 6 > (1/3)(1) + 4 true? YES. So we know that (1, 6) is a solution of y > (1/3)x + 4. Because (1, 6) lies ABOVE the line y = (1/3)x + 4, we can conclude that all points abovve this line are solutions.

6 0

3 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

2 years ago

matrenka [14]

Answer:

Step-by-step explanation:

D.works many year for a nation

8 0

2 years ago

Which equation best represents the relationship between x and y ?

Klio2033 [76]

Answer:

ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

7 0

2 years ago