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Lena [83]
3 years ago
7

Need to know the answer I don't get it

Mathematics
1 answer:
Svetllana [295]3 years ago
4 0
The first two are alike because you have to add 3 to each side for everything to come out even.
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Can someone help simplify?: -8x^3y2(2x^4y^4)
Kisachek [45]

So the rule with multiplying exponents of the same base is to add the exponents together. Applying this rule here would look like this:

-8x^3y^2*2x^4y^4=(-8*2)x^{3+4}y^{2+4}=-16x^7y^6

In short, your simplified expression is going to be -16x^7y^6.

3 0
3 years ago
Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10
damaskus [11]

Answer:

4

Step-by-step explanation:

set

f(x,y)=x+y\\

constrain:

g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10

Partial derivatives:

f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2

Lagrange multiplier:

grad(f)=a*grad(g)+b*grad(h)\\

\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]

4 equations:

1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10

By solving:

a=4/9\\b=-2/27\\x+y=4

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4

The maximum is 4

6 0
3 years ago
France can complete 91 oil changes in 7 days how may oil changes can frances complete in 7 days
arsen [322]
Let oil change be x
91 / 7 = x / 11
(91 * 11) / 7 = x
13 * 11 = x
<span>143 = x Ans</span>
8 0
3 years ago
Write the polynomial in factored form.<br><br> x^3−3x^2−10x
kirill115 [55]

Answer:

x( x − 5 ) ( x + 2 )

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
the vertex of this parabola is at (5,5). when the x-value is 6, the y-value is -1. what is the coefficient of the squared in the
zlopas [31]

Answer: OPTION D.

Step-by-step explanation:

The vertex form of a quadratic function is:

y= a(x - h)^2 + k

Where (h, k) is the vertex of the parabola and "a" is the coefficient of the squared in the parabola's equation.

We know that the vertex of this parabola is at (5,5) and we also know that when the x-value is 6, the y-value is -1.

Then  we can substitute values into  f (x) = a(x - h)^2 + k and solve for "a". This is:

-1= a(6- 5)^2 + 5\\\\-1=a+5\\\\-1-5=a\\\\a=-6

7 0
3 years ago
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