So the rule with multiplying exponents of the same base is to add the exponents together. Applying this rule here would look like this:

In short, your simplified expression is going to be -16x^7y^6.
Answer:
4
Step-by-step explanation:
set

constrain:

Partial derivatives:

Lagrange multiplier:

![\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5Cend%7Barray%7D%5Cright%5D%3Da%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2x%5C%5C2y%5Cend%7Barray%7D%5Cright%5D%2Bb%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3x%5E2%5C%5C3y%5E2%5Cend%7Barray%7D%5Cright%5D)
4 equations:

By solving:

Second mathod:
Solve for x^2+y^2 = 7, x^3+y^3=10 first:

The maximum is 4
Let oil change be x
91 / 7 = x / 11
(91 * 11) / 7 = x
13 * 11 = x
<span>143 = x Ans</span>
Answer:
x(
x
−
5
)
(
x
+
2
)
Step-by-step explanation:
Answer: OPTION D.
Step-by-step explanation:
The vertex form of a quadratic function is:

Where (h, k) is the vertex of the parabola and "a" is the coefficient of the squared in the parabola's equation.
We know that the vertex of this parabola is at (5,5) and we also know that when the x-value is 6, the y-value is -1.
Then we can substitute values into
and solve for "a". This is: