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2 years ago

Help solve #2 please

Mathematics

1 answer:

borishaifa [10]2 years ago

5 0

its pithagoreon so

c^2= a^2+ b^2

c^2= 32^2 +24^2

c^2= 1,024+576

c^2= 1600

c= $\sqrt{1600\\$ = 40

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$\bf \textit{Cofunction Identities}
\\ \quad \\
\boxed{sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})}\qquad 
cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
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\\ \quad \\ \quad \\
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-------------------------------\\\\$

$\bf \begin{array}{lcllclll}
sin(&90^o-\theta)&=&cos(&\theta)\\
&\uparrow &&&\uparrow \\
&3x+15&&&7x-2\\
&\downarrow \\
&90-(7x-2)
\end{array}
\\\\\\
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