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Stells [14]
4 years ago
12

Which of the following is the function T(a) if T^-1(a)=11a-2

Mathematics
1 answer:
SpyIntel [72]4 years ago
5 0

Answer:

T(a) =(a+2)/11

Step-by-step explanation:

The inverse of the inverse is the function

To find the inverse let T^-1(a) be y

y = 11a -2

Exchange y and a

a = 11y -2

Solve for y

Add 2 to each side

a+2 = 11y -2 +2

a+2 =11y

Divide each side by 11

(a+2)/11 =y

T(a) =(a+2)/11

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1+ 3z= 40 what’s the answer to this problem I’m confused???
stepan [7]

Answer:

13

Step-by-step explanation:

subtract 1 on both sides

then divide by 3

to get 13

8 0
3 years ago
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Tickets to the school musical are $5.00 for adults and $3.50 for students. If the total value of the tickets sold was $2517.50 a
stealth61 [152]
To answer this, you will write and equation in terms of the number of adult tickets sold and then solve for a, the number of adult tickets.

$5a + $3.50s = $2517.50
$5a + $3.50(a + 100) = $2517.50
5a + 3.50a + 350 = 2517.50
         8.50a  -350      -350
                  <u>8.5a</u>  = <u>2167.50</u>
                  8.5         8.5
    a = 255
The number of adult tickets sold was 255, and the number of student tickets sold was 355 (255 +100).


7 0
3 years ago
A pair of shoes that originally cost $47.50 is on sale for 25% off. What is the sale price? $40.52, $59.38, $35.63, $11.88
statuscvo [17]

Answer:

35.63

Step-by-step explanation:

3 0
3 years ago
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the rain gauge shows 3 centimeters of water which equation gives height h it rains at a rate of 0.25 centimeters per hour after
Vilka [71]
0.25t = 3 is the equation or 0.25t = h but the first one would be used to solve it i think 
8 0
3 years ago
find the value of the trigonometric function sin (t) if sec t = -4/3 and the terminal side of angle t lies in quadrant II
kodGreya [7K]

Answer:

sin(t) =\frac{\sqrt{7}}{4}

Step-by-step explanation:

By definition we know that

sec(t) = \frac{1}{cos(t)}

and

cos ^ 2(t) = 1-sin ^ 2(t)

As sec(t) = -\frac{4}{3}

Then

sec(t) = -\frac{4}{3}\\\\\frac{1}{cos(t)} =-\frac{4}{3}\\\\cos(t) = -\frac{3}{4}

Now square both sides of the equation:

cos^2(t) = (-\frac{3}{4})^2

cos^2(t) = \frac{9}{16}\\\\

1-sin^2(t) =\frac{9}{16}\\\\sin^2(t) =1-\frac{9}{16}\\\\sin^2(t) =\frac{7}{16}\\\\sin(t) =\±\sqrt{\frac{7}{16}}

In the second quadrant sin (t) is positive. Then we take the positive root

sin(t) =\sqrt{\frac{7}{16}}

sin(t) =\frac{\sqrt{7}}{4}

8 0
3 years ago
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