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Stells [14]
3 years ago
12

Which of the following is the function T(a) if T^-1(a)=11a-2

Mathematics
1 answer:
SpyIntel [72]3 years ago
5 0

Answer:

T(a) =(a+2)/11

Step-by-step explanation:

The inverse of the inverse is the function

To find the inverse let T^-1(a) be y

y = 11a -2

Exchange y and a

a = 11y -2

Solve for y

Add 2 to each side

a+2 = 11y -2 +2

a+2 =11y

Divide each side by 11

(a+2)/11 =y

T(a) =(a+2)/11

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Phoenix [80]

8.99 \times (100\% + 8.25\%) \\  = 8.99 \times 108.25\% \\  = 9.732

Answer : Mrs Thomas will need the amount of $9.73 to cover her garden.

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3 years ago
Children pick their favorite sports team 35% pick basketball 28% pick hockey what percent pick football
Kay [80]
37% pick football

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2 years ago
What are the different types of sampling
ElenaW [278]

Answer:

they are:

1. random

2. systematic

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3 0
3 years ago
Carl bought 24 daisies and roses. Daisies cost $0.25 each and roses cost $0.90 each. If
yuradex [85]

Answer:

Roses= $8.4

Daises= $15.6

Step-by-step explanation:

Let represent the daises and let r represent d roses

r + d= 24....equation 1

0.25r + 0.90d= 16.40.......equation 2

r= 25-d

Substitute 25-d for r in equation 2

0.25(25-d) + 0.90d= 16.40

6.25-0.25d+0.90d= 16.40

6.25+0.65d= 16.40

0.65d= 16.40-6.25

0.65d= 10.15

d= 10.15/0.65

d = 15.6

Sub 15.6 for d in equation 1

r+d= 24

r+15.6= 24

r= 24-15.6

= 8.4

Price of daises is $15.6

Roses is $8.4

4 0
3 years ago
In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine
zimovet [89]

Answer:

(a)  0.2650

(b)  0.0111

(c)  0.0105

(d)  0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15.       &;

If the area of the agar plate is 75cm²;

what is the probability  of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean  μ = 15  

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates =  15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

X \sim N (\mu = 75 , \sigma^2 = 75)

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d)  Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

=  0.0111 - 0.0105

= 6*10^{-4}

= 0.0006 to four decimal places

5 0
3 years ago
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