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lubasha [3.4K]
3 years ago
13

Find the equation of the line passing through (-7,-9) and perpendicular to 8x-9y +2=0

Mathematics
1 answer:
notka56 [123]3 years ago
5 0
8x - 9y + 2 = 0
-9y = -8x - 2
y = 8/9x + 2/9.....the slope here is 8/9. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will need a slope of -9/8 (see how I flipped the slope and changed the sign)

y = mx + b
slope(m) = -9/8
(-7,-9)...x = -7 and y = -9
now we sub and find b, the y int
-9 = (-9/8)(-7) + b
-9 = 63/8 + b
-9 - 63/8 = b
-72/8 - 63/8 = b
-135/8 = b

so ur perpendicular equation is : y = -9/8x - 135/8
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1. consider a lottery with three possible outcomes: $125 will be received with probability 0.25, $100 will be received with prob
tigry1 [53]

The lottery's anticipated worth is $80.

Given that,

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4 0
1 year ago
Read 2 more answers
I need help on this problem please help
Masteriza [31]
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5 0
3 years ago
Change the line 3x − 8y = 5 into slope-intercept form.
Nimfa-mama [501]
Slope is y=mx+b
m=slope
b=y intercept

solve for y basically


3x-8y=5
minus 3x both sides
-8y=-3x+5
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y=\frac{3}{8}x-\frac{5}{8}
4 0
3 years ago
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