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storchak [24]
3 years ago
8

What is the average rate of change for the function f(x)=3x^2 -5 on the interval −3 ≤ x ≤ −1 ?

Mathematics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

-12

Step-by-step explanation:

Let b = -1 and a = -3

The average rate of change = \frac{f(b) - f(a)}{b - a}

f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2

f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22

f(b) - f(a) = -2 - 22 = -24

b - a = -1 + 3 = 2

\frac{f(b) - f(a)}{b - a} = -24/2 = -12

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snow_lady [41]

Answer:

The area of the figure is (100 + 50π) cm²

The area of the figure is 257.1 cm² to the nearest tenth

Step-by-step explanation:

<em>The figure is consists of a square with side length 10 cm, and four semi-circles the diameter of each one is equal to the side length of the square</em>

Area of the figure = area of square + 4 × area of a semi-circle

  • Area of a square = s², where s is the length of its side
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∵ The length of the side of the square is 10 cm

∴ s = 10 cm

∵ Area of the square = s²

∴ Area of the square = (10)² = 100

∴ Area of the square is 100 cm²

∵ The diameter of the circle is equal to the side of the square

∴ The diameter of the circle = 10 cm

∵ The radius of a circle is half the diameter of the circle

∴ The radius of the semi-circle = \frac{1}{2} × 10 = 5

∴ The radius of the semi-circle = 5 cm

Now lets find the area of a semi-circle

∵ Area of semi-circle = \frac{1}{2} πr²

∴ Area of semi-circle = \frac{1}{2} π(5)² = 12.5π

∴ Area of each semi-circle is 12.5π cm²

Lets find the area of the figure

∵ Area figure = Area of square + 4 × area of a semi-circle

∴ Area figure = 100 + 4 × 12.5π

∴ Area figure = 100 + 50π

∴ The area of the figure is (100 + 50π) cm²

Substitute π by its value in the calculator

∴ Area figure = 100 + 50(3.141592654)

∴ Area figure = 257.0796327

- Round it to the nearest tenth

∴ The area of the figure is 257.1 cm²

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