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2 years ago

What is the average rate of change for the function f(x)=3x^2 -5 on the interval −3 ≤ x ≤ −1 ?

Mathematics

1 answer:

Anestetic [448]2 years ago

4 0

Answer:

-12

Step-by-step explanation:

Let b = -1 and a = -3

The average rate of change = $\frac{f(b) - f(a)}{b - a}$

f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2

f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22

f(b) - f(a) = -2 - 22 = -24

b - a = -1 + 3 = 2

$\frac{f(b) - f(a)}{b - a}$ = -24/2 = -12

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Mary and Jane both took PSY230 last semester but they were in two different sections taught by different professors. Mary's clas

Greeley [361]

Answer:

Due to the higher z-score, Jane did better in class.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

Whoever's grade had the better z-score did better in class.

Mary's:

Mean of 85, standard deviation of 5, grade of 88. This means that $\mu = 85, \sigma = 5, X = 88$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{88 - 85}{5}$

$Z = 0.6$

Jane's

Mean of 80, standard deviation of 10, grade of 88. This means that $\mu = 80, \sigma = 10, X = 88$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{88 - 80}{10}$

$Z = 0.8$

Due to the higher z-score, Jane did better in class.

4 0

2 years ago

Awnser and show your work <3

marishachu [46]

Answer:

Team A: 25 players

Team B: 24 players

Step-by-step explanation:

Team A:

to find the total # of players of the team we need to set up a fraction. 5 out out of an unknown number of players is equal to 1/5, so we set it up as:

$\frac{5}{x} = \frac{1}{5}$