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3 years ago

29 pointssssssssssssssssssssssssssssss

Mathematics

2 answers:

tangare [24]3 years ago

7 0

The first one.

6+x=42

ss7ja [257]3 years ago

6 0

The answer and the reason for the answer is all in the oicture.

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There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes ther

rodikova [14]

Answer: a) Number of nickels, dimes, and quarters are 80, 120, 300 respectively.

b) The coins are worth of 91 dollars i.e. $91 in the piggy bank.

Explanation:

Since we have given that

For every 2 nickels there are 3 dimes ,

So, their ratio will be 2:3

and for every 2 dimes there are 5 quarters.\,

So, their ratio will be 2:5

Now, we'll first find the ratio of nickles to dimes to quarters i.e.

Nickle Dimes Quarters

2 3

2 5

So, it becomes ,

Nickle : Dimes : Quarters

2×2 : 3×2 : 3×5

4 : 6 : 15

Now, let the number of nickle be 4x

Let the number of dimes be 6x

Let the number of quarters be 15x

According to question,

$4x+6x+15x=500\\\\25x=500\\\\x=\frac{500}{25}=20$

So, number of nickels is given by

$4x=4\times 20=80$

Number of dimes is given by

$6x=4\times 20=120$

Number of quarters is given by

$15x=4\times 20=300$

As we know that

$1\ nickel=5\ cents\\\\1\ dime=10\ cents\\\\1\ quarter=25\ cents$

So, According to our question, we get

$80\times 5+120\times 10+300\times 25=400+1200+7500=9100\ cents\\\\1\ cent=0.01\ dollar\\\\9100\ cents=9100\times 0.01\ dollars=91\ dollars.$

Hence,

a) Number of nickels, dimes, and quarters are 80, 120, 300 respectively.

b) the coins are worth of 91 dollars i.e. $91 in the piggy bank.

7 0

3 years ago

oint) Solve the following inequality. Enter the answer in interval notation. 10x - 5 < -10(8x - 2)+3 Answer: Note: If the ans

nevsk [136]

$10x - 5 < - 10(8x - 2) + 3 \\ 10x < - 80x + 20 + 8 \\ 90x < 28 \\ x < \frac{14} {45}\\x \in (-\infty,\frac{14}{45} )$

6 0

3 years ago

Classify: -5x3-11x2+x

Usimov [2.4K]

-15-22+x

-36+x

I think that's the answer (at least that's what I got) hope this helps★

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3 years ago

Alex accidentally forgot to stock up on toilet paper before the stay-at-home order. Now he has to buy toilet paper on the black

gladu [14]

<h2>Alex accidentally forgot to stock up on toilet paper before the stay-at-home order. Now he has to buy toilet paper on the black market. Though the price of toilet paper on the black market has mostly stabilized, it still varies from day to day. The daily price of a generic brand 12-pack, X, and the daily price of a generic brand 6-pack, Y, (in rubles) jointly follow a bivariate normal distribution with: </h2><h2>μx = 2,470, σx = 30, μy = 1,250, σ = 25, p = 0.60. </h2><h2>(a) What is the probability that 2 (two) 6-packs cost more than 1 (one) 12-pack? (b) To ensure that he will not be without toilet paper ever again, Alex buys 7 (seven) 12-packs and 18 (eighteen) 6-packs. What is the probability that he paid more than 40,000 rubles? </h2><h2>(c) Suppose that today's price of a 12-pack is 2,460 rubles. What is the probability that a 6-pack costs less than 1,234 rubles today? [1 US dollar is approximately 75 rubles ]</h2>

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3 years ago

What is 1/7^9 × 1/7^-6

artcher [175]

$\bf \cfrac{1}{7^9}\cdot \cfrac{1}{7^{-6}}\implies \cfrac{1\cdot 1}{7^9\cdot 7^{-6}}\implies \cfrac{1}{7^{9-6}}\implies \cfrac{1}{7^3}\implies \cfrac{1}{343}$

5 0

3 years ago