Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell
(2.5 m/s) x (45 s) = 112.5 meters .
If it wound up only 40 meters underwater, then it must have fallen
(112.5 m - 40 m) = 72.5 meters
from its storage position on the big cruise ship,
before it ever reached the water.
Since it was falling at the rate of 2.5 m/s, it took
(72.5 m) / (2.5 m/s) = 29 seconds
to get down to the water surface after it started dropping.
Hey there!
m(4 + 7)
= 1m(4 + 7)
DISTRIBUTE m WITHIN the PARENTHESES
= m(4) + m(7)
= 4(m) + 7(m)
= 4(1m) + 7(1m)
= 4m + 7m
COMBINE the LIKE TERMS
= 11m
Therefore, your answer is: 11m
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
Answer:
It is 2 hours, 22 minutes, 48 seconds.
The 2 is obviously 2 hours. For the minutes, .38 * 60 = 22.8, so the minutes is 22. 0.8 * 60 = 48. So 2 hours, 22 minutes and 48 seconds.
If you divid 8.4 x 107 and 3 x 103 you should get 2.8 x 104
Answer:
ratio of GEOM to TEYR is 
Therefore OE is equal to:


12 units is the length of OE, so the final answer is:
12.0 Units.