When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.

The coefficient of the squared term is 1/36.

8 0

3 years ago

What is the value of numerical expression 5/8 - 5/12 (3-1/4)+2/3

makvit [3.9K]

It would be 7/48 or the decimal would be 0.15

8 0

3 years ago

Marlon asks a friend to think of a number from 5-11. What is the probability that marlins friend will think of the number 9

Tju [1.3M]

Answer:

14.29% probability that Marlon's friend will think of the number 9

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

There are 7 numbers from 5 to 11(5,6,7,8,9,10,11)

9 is one of them

$p = \frac{1}{7} = 0.1429$

14.29% probability that Marlon's friend will think of the number 9

4 0

3 years ago