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lesantik [10]
2 years ago
5

An elevator has a weight limit of less than 900 pounds. A student weighing 95 pounds get on the elevator. Write and Solve an ine

quality to represent the remaining weight, x, that can be added. Put your solved answer in the blank. It will be written as an inequality
Mathematics
1 answer:
sergiy2304 [10]2 years ago
3 0

Given:

An elevator has a weight limit of less than 900 pounds.

A student weighing 95 pounds get on the elevator.

To find:

The inequality to represent the remaining weight, x, that can be added.

Solution:

Let x be the remaining weight that can be added.

A student weighing 95 pounds get on the elevator.

So, total weight on the elevator = x+95 pounds.

An elevator has a weight limit of less than 900 pounds.  It means, total weight on elevator must be less than 900 pounds.

x+95

Subtracting 95 from both sides.

x

x

It means, the remaining weight that can be added is less than 805 pounds.

Therefore, the required inequality is x.

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A cylinder has a height of 4 meters and a radius of 1.5 meters. What is the approximate radius of a sphere that has the same sur
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If the surface area of the cylinder is 12π square meters. Then the radius of the sphere will be 1.7 meters.

<h3>What is a cylinder?</h3>

A cylinder is a closed solid that has two parallel circular bases connected by a curved surface.

A cylinder has a height of 4 meters and a radius of 1.5 meters.

Then the approximate radius of a sphere that has the same surface area as the cylinder.

We know that the Surface area of the cylinder will be is given as

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Then we have

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                                   r = 1.7 meters

More about the cylinder link is given below.

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2 years ago
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Answer:

Lines RQ and SP are perpendicular to SR

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3 years ago
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mihalych1998 [28]

Answer:

2nd option

Step-by-step explanation:

You're goal is to isolate b by itself. The only part you need to worry about is the equation, the rest of the word problem is irrelevant.

The whole process of solving this is to do PEMDAS in reverse.

So first add/subtract all the values that does not have a <em>b</em> attach to it to the other side.

then multiply/divide all the values that is not a <em>b</em> to get the b-value by itself

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