Answer:
x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Step-by-step explanation:
1−2sin2 x≤−sin x ⇒ (2sin x+1)(sin x−1)≥0
sin x≤−1/2 or sin x≥1
−5π/6+2nπ≤x≤−π/6+2nπ or , n ϵ I x=(4n+1)π/2, n ϵ I⇒ -5π6+2nπ≤x≤-π6+2nπ or , n ϵ I x=4n+1π2, n ϵ I (as sin x = 1 is valid only)
In general⇒ In general x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Answer:
v = -5
Step-by-step explanation:
Step 1: Write out equation
-8 + 5v = -33
Step 2: Add 8 on both sides
-8 + 8 + 5v = -33 + 8
5v = -25
Step 3: Divide both sides by 5
5v/5 = -25/5
v = -5
10(1/2x + 5) = 7
That's the way to write the description of that equation. Good luck!!
B. =
.60=.6
its just like 60 and 060 the 0 is useless
Answer:
5y
Step-by-step explanation:
subtract 8 from 3
