All categories

3 years ago

Solve for v. -8 +5v=-33

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

Answer:

Solve

-8 +5v=-33

So 5v=-33+8

(-8 became 8 because we brought it back to the other side to have the v 《5v》 alone and the numbers alone )

5v= -25

So v=-25/5

We simplify -25/5

v=-5

Dima020 [189]3 years ago

3 0

Answer:

v = -5

Step-by-step explanation:

Step 1: Write out equation

-8 + 5v = -33

Step 2: Add 8 on both sides

-8 + 8 + 5v = -33 + 8

5v = -25

Step 3: Divide both sides by 5

5v/5 = -25/5

v = -5

You might be interested in

Simplify the trigonometric expression.

marusya05 [52]

Answer:

from the working in the photo

4 0

2 years ago

If 4 people share a meal a one person pays £17.50 how much does the meal cost

Ostrovityanka [42]

The meal costs 4.37500

8 0

3 years ago

-3/10x (-0.1) can you please help ASAP

Gre4nikov [31]

$\frac{ - 3}{10} \times ( - 0.1)$

$\frac{ - 3}{10} \times \frac{ - 1}{10}$

–3 × –4

$\frac{12}{10}$

$\frac{6}{5} answer$

<h3>HOPE THIS HELPS :)</h3>

8 0

2 years ago

What is the y-intercept of the line perpendicular to (1,1) and (-3,-1) and passes through (-3,-2)

marin [14]

Answer:

-8

Step-by-step explanation:

Let's first establish the reference line (the one that the second line will be perpendicular to). We are told that this line passes through two points:

(1,1) and (-3,-1).

We'll find a line equation using the point slope form format to start:

(y - y1) = m * (x - x1), where m is the slope and the x and y are from two points.

(x,y) = (1,1)

(x1,y1) = (-3,-1)

Rearrange the equation:

(y - y1) = m * (x - x1)

m = (y - y1)/ (x - x1)

m = (1-(-1))/(1-(-3))

m = 2/4, or 1/2: The slope is 1/2. [This is "m."]

We can use the slope-intercept form for this line (y=mx + b) and then calculate b, the y-intercept:

y = (1/2)x + b

Use either of the two given points. I'll use (1,1) since I have memorized the "1" math tables.

y = (1/2)x + b

1 = (1/2)(1) + b for (1,1)

b = 1/2

This makes the reference line: y = (1/2)x+(1/2)

===

The line perpendicular must have a slope that is the negative inverse of (1/2). This would be -(2/1), or -2.

We can then write y = -2x + b

To find be, enter the one given point for this line: (-3,-2)

y = -2x + b

-2 = -2(-3) + b

-2 = 6 + b

b = -8

The perpendicular line is thus:

y = -2x - 8

It has a y-intercept of -8

5 0

2 years ago

Which point is collinear with points a and d

Art [367]

B. (6, -8)

First, you need to figure out the slope of the line

(y1 - y2) / (x1 - x2)

After substituting points D(-3, 4) A(3, -4)

[4 - (-4)] / (-3 - 3)
(8) / (-6)

The slope of the line is -8/6 or -4/3 simplified

Then you can put it in point slope form:

(y - y1) = m(x - x1)

(y - y1) = -4/3(x - x1)

The point that I am using for point slope form is A(3, -4)

[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)

Next you have to simplify the equation so that y is isolated

y + 4 = -4/3(x - 3)

First distribute the -4/3

y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4

Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x

Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal

For example) (6, -8)
-8 = -4/3(6)
-8 = -8

So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D

~~hope this helps~~

6 0

3 years ago

Solve for v. -8 +5v=-33​

Solve for v. -8 +5v=-33