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3 years ago

The true or false questions. 1.egrep can accept multiple filenames as input arguments.

Computers and Technology

1 answer:

BlackZzzverrR [31]3 years ago

5 0

Answer: True

Explanation: yes, it is true that egrep can accept multiple filenames as input arguments for example egrep -r "text1/text2", so this will search in all the sub directories . E grep is also known as 'grep -E' which belongs to the group of grep function and we used egrep to separate multiple patterns for OR conditions. This is also very less time consuming if you are going to search multiple input arguments in multiple different logs at the same time.

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Professor Zak allows students to drop the four lowest scores on the ten 100 point quizzes she gives during the semester. Design

lana66690 [7]

Answer:

Explanation:

Let's do this in Python, we will accept 2 arguments, the student name and an array of the 10 scores. The function would sort the scores out, get the last 6 scores, take the sum and finally out put them with the student name:

def total_six_highest_score(name, scores):

scores.sort()

highest_six_scores = scores[4:]

total_highest = sum(highest_six_scores)

return name, total_highest

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3 years ago

The BasicSet 2 class implements the Set ADT by wrapping an object of the Linked Collection class and:______.

Trava [24]

Answer:

The BasicSet 2 class implements the Set ADT by wrapping an object of the Linked Collection class and forwarding" all method calls except certain calls to the add method.

8 0

3 years ago

Someone please help ASAP will brainlist

Arada [10]

Answer:

i cant help

Explanation:

4 0

2 years ago

Read 2 more answers

How many nibbles make one kilobyte

Kazeer [188]

2000 nibbles I think correct me if I’m wrong

5 0

2 years ago

Read 2 more answers

Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl

Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

small = num1

if num1 > num2:

small = num2

for i in range(1, small+1):

if((num1 % i == 0) and (num2 % i == 0)):

gcd = i

print("The GCD is "+ str(gcd))

def LCM(num1,num2):

big = num2

if num1 > num2:

big = num1

while(True):

if((big % num1 == 0) and (big % num2 == 0)):

lcm = big

break

big = big+1

print("The LCM is "+ str(lcm))

print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

if num1 > num2:

small = num2

The following iteration determines the GCD of num1 and num2

for i in range(1, small+1):

if((num1 % i == 0) and (num2 % i == 0)):

gcd = i

This line prints the GCD

print("The GCD is "+ str(gcd))

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

big = num2

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

if num1 > num2:

big = num1

The following iteration continues while the LCM has not been gotten.

while(True):

This if statement determines the LCM using modulo operator

if((big % num1 == 0) and (big % num2 == 0)):

lcm = big

break

big = big+1

This line prints the LCM of the two numbers

print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

See attachment for more structured program

Download txt

5 0

3 years ago