<u>Answer:</u>
The correct answer option is D. set the switch to the highest range and then move it to a range that gives the most accurate reading.
<u>Explanation:</u>
When measuring an unknown voltage with an analog VOM, one should set the meter to the highest range and then move it to a range that gives the most accurate reading.
The reason being that the analog meters indicate the measurement of voltage by moving a needle across a physical card by printing numbers on it.
So in case the voltage is nearly 100 times the full range to which the meter is set, then its needle will try move to a position which will be 100 times the highest number on the meter.
Answer
NO sorry
Have a great day
a = int(input("Class A tickets sold: "))
b = int(input("Class B tickets sold: "))
c = int(input("Class C tickets sold: "))
print("Total income generated: $"+str((a*20)+(b*15)+(c*10)))
I hope this helps!
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
