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Marrrta [24]
3 years ago
15

What is the solution of sqrt1-3x=x+3

Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0

x = - 1

given \sqrt{(1-3x)} = x + 3

square both sides

1 - 3x = (x + 3 )² ( expand right side using FOIL )

1 - 3x = x² + 6x + 9 ( subtract 1 - 3x from both sides )

0 = x² + 9x + 8

0 = ( x + 1)(x + 8)

equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = -1

x + 8 = 0 ⇒ x = - 8

As a check

substitute these values into the equation and if both sides are equal then they are the solutions

x = - 1 : \sqrt{1+3 } = 2 and - 1 + 3 = 2 ← true

x = - 8 : \sqrt{1+24} = 5 and - 8 + 3 = -5 ← false

thus the only solution is x = - 1


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