The complete question in the attached figure
we know that
The Exterior Angle Theorem establishes that t<span>he measure of an exterior angle of a triangle equals to the sum of the measures of the two remote interior angles of the triangle.
so
the answer is the option</span><span>
A. the remote interior angles</span>
<span> -5a^2-19a^2-5a-8+12a^2-22-14a-2a
first gather all same powers
-5a</span>²-19a²+12a²-5a-14a-2a-8-22
-12a²-21a-30
-3(6a²+7a-+10)
He sold all general admission tickets
Can prove using simultaneous equations
50x + 60y = $1050
x + y = 21 => y = 21-x
50x + 60(21-x) = 1050
50x + 1260 - 60x = 1050
-10x = 1050 - 1260
-10x = -210
x = -210/-10
x = 21
x + y = 21
21 + y = 21
y=0
Since he sold 21 general admission tickets and no VIP tickets
Answer:
b.(-2, -1), (3, 4)
Step-by-step explanation:
We are given function as

We can verify each intervals
At (-6,-5):
Firstly we will plug x=-6

now, we can plug x=-5

since, both are positive values
So, zeros can not lie between them
At (-4,-3):
Firstly we will plug x=-4

now, we can plug x=-3

since, both are positive values
So, zeros can not lie between them
At (-2,-1):
Firstly we will plug x=-2

now, we can plug x=-1

since, one is positive and another is negative
So, zeros will lie between them
At (3,4):
Firstly we will plug x=3

now, we can plug x=4

since, one is positive and another is negative
So, zeros will lie between them
zeros will be between
(-2, -1), (3, 4)