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masha68 [24]
3 years ago
14

X|x integars between 4 & 8 lost the elements in the set​

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0

Answer:

The set of integer between 4 and 8 = { 5, 6, 7 }.

Step-by-step explanation:

Set:

A set is a well-defined  collection of distinct objects, elements encloses in curly bracket.  

For example.

set of vowels = { a, e, i, o, u }

set of any three Capital alphabets = { A, B ,Z }

set of cars = { Ferrari, Volvo, Mercedes, Audi }

Now we want set of integer between 4 and 8

Integer: All the positive and negative natural numbers are called integers.

-1, -2, -3, 1, 2, 3, 4, 5, 6 ,7 , 8 ..

The set of integer between 4 and 8 = { 5, 6, 7 }.

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Answer:

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Step-by-step explanation:

If x is 7, then 7 * 2 = 13, and 14 - 1 = 13.

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Solve.<br> 92.5÷105 brainliest
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Answer:

\frac{37}{42}

Step-by-step explanation:

Given :

\frac{92.5}{105}

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\frac{92.5}{105} \times\frac{2}{2}

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1 year ago
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Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
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Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

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Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

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Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

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