Odd numbers end with 1 or 3 or 5 or 7 or 9
alrighty, the last number can be 1 or 3 or 7 or 9 (we aren't given 5 in the set)
4 choices for the last number
for the other 2 numbers, we can use any other numbers
6 numbers in the set
6 choices for the first digit
5 for the 2nd
4 for the 3rd digit
so there are 6*5*4 or 120 different odd numbers that can be constructed withthe given numbers in the set
Let a, b and c be 3 numbers whose Greatest Common Factor is 13.
This means that all a, b, and c are multiples of 13, and the three of them have no other common factor (except1)
So we can construct a, b and c as follows:
a=13*2*3, b=13*2*5, c = 13*7
a=78, b=130, c=91
Answer: {78, 130, 91}
Answer:
21.3776
Step-by-step explanation: