9514 1404 393
Answer:
3.347 N
Step-by-step explanation:
The vertical component of the dragging force is (120 N)/√2, so the net downward force is the difference between that due to gravity and the upward component of the dragging force.
(9.8 m/s²)(9 kg) -(120 N)/√2 = 3.347 N
The normal force acting on the log is 3.347 N.
Answer:y=15
3 y
___=___
15 75
cross multiply
15y=225
divide both sides by 15
y=15
28 (unit)^2
find the differences in the x (4) and y (7) coordinates
times them together as you normally find the area of rectangle (L×W)
Answer:
15r²-14r-8
Step-by-step explanation:
Use FOIL for this:
(5r+2)(3r-4)
First: 5r × 3r = 15r²
Outer: 5r × (-4) = -20r
Inner: 2 × 3r = 6r
Last: 2 × (-4) = -8
15r²-20r+6r-8=
15r²-14r-8