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4 years ago

Which statements are true for the given quadrilaterals?

2 answers:

7 0

The answer is C because all the other answers are false. A rhombus does not have right angles, which is a characteristic of a rectangle. A rhombus does not have right angles - it has two obtuse and two acute. All rectangles are not squares because the sides need not have equal length. That leaves C. Parallelograms have 4 sides, which makes them a variety of quadrilateral

Goshia [24]4 years ago

3 0

c and a because because parallelograms have four sides an

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Pls help me solve pls show how you got the answer

jeyben [28]

Answer:

Step-by-step explanation:

p=8 cm

one side=8/4=2 cm

edge of black square=2/4=1/2 cm=0.5 cm

area of one square=(0.5)²=0.25 cm²

total area of two black squares=2×0.25=0.5 cm²

length of white rectangle=2/2=1 cm

width=2/4=1/2 cm=0.5 cm

area of one rectangle=1×0.5=0.5 cm²

area of two rectangles=2×0.5=1 cm²

total area=0.5+1=1.5 cm ²

7 0

3 years ago

An initial investment of $100 is now valued at $150. The annual interest rate is 5%, compounded continuously. The equation 100e0

nikitadnepr [17]

Answer:

$8\ years$

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\ P=\$100\\A=\$150\\ r=0.05$

substitute in the formula above

$150=100(e)^{0.05*t}$

$1.5=(e)^{0.05*t}$

Applying ln both sides

$ln(1.5)=(0.05t)ln(e)$

$ln(1.5)=(0.05t)$

$t=ln(1.5)/(0.05)$

$t=8\ years$

8 0

3 years ago

Read 2 more answers

In game 1 emerson struck out 30 times in 90 times at bat in game 2 he struck out 40 times in 120 times at bat

Agata [3.3K]

Answer:

a) 32

b) 67.613

Step-by-step explanation:

In Game 3, Emerson struck out 42 times in 140 times at-bat.

Part A

Drag numbers to complete the proportion to represent the percent of strikeouts per at-bats.

Numbers may be used once or not at all.

Part B

What percentage of times at bat did Emerson actually hit the ball?

Part A

Total number of strikeouts= 30+40+42= 112

Total number of at bats = 90+120+140= 350

strikeouts : times

112: 350

p:100

Using cross product rule

p/100= 112/350

p * 350= 112*100

or p= 11200/350= 32

It means that there were 32 strikeouts if 100 times were bat at hits.

Part B:

Total number of strikeouts= 30+40+42= 112

Total number of at bats = 90+120+140= 350

But we need the percentage of times at bat hit

Therefore

Hits= times - strikeouts= 350-112= 238

Percentage = 238/352*100= 67.613

Check

The above answers are correct because

100-32 = 68

68 ≅ 67.613

7 0

3 years ago

Pay: $15.31 per hour Hours: 9 hours per week per week per month per year

adoni [48]

Answer : 137.79 per week

459.30 per month

5588.15 per year

Step-by-step explanation:

8 0

4 years ago

What is the volume of a rectangular pyramid with a height of 5.2 meters and a base 8 meters by 4.5 meters

dezoksy [38]

Answer:

62.4

Step-by-step explanation:

1/3*5.2*4.5*8=62.4

7 0

3 years ago

Read 2 more answers