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shtirl [24]
3 years ago
10

a card is chosen at random from a deck of 52 cards it is then replaced and a second card is chosen what is the probability of ge

tting a jack and then an eight
Mathematics
2 answers:
castortr0y [4]3 years ago
6 0
There are 4 jacks and 4 eights so with replacement:

P(Jand8)=(1/13)^2=1/169
Pachacha [2.7K]3 years ago
4 0
Their are 4 Jacks in a set of 52 cards so the probability to get a jack = 4/52=1/13 same for the eights

The cards was replaced then the total number of card is still 52. Now after selecting a Jack, you want to select an eight.

This is a conditional probability select a jack AND select an eight
P(Jack AND eight) = 1/13 x 1/13 - 1/169 = 0.006 or 0.6%
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What do you need help with? it helps us to know the question!
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3 years ago
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sveticcg [70]

Answer:

80 ounces

Step-by-step explanation:

In one pint, there is 16 ounces. Thus, if she picked five pints, 16 × 5 = 80 ounces.

Another way to solve this problem is by setting a proportion.

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Therefore, the answer is 80 ounces.

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2 years ago
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set them equal to their sum. which in this case is 141 then solve for x and plug it into your original equation to get your answer.

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3 years ago
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dlinn [17]

Answer:

V = pi * R^2 * h

R = (V / (pi * h))^1/2 = (141.3 / (3.14 * 5))^1/2 = 3 cm

8 0
3 years ago
Help! Check answer? My answer x=80
GuDViN [60]
The is the correct answer x=80
8 0
3 years ago
Read 2 more answers
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