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shtirl [24]
3 years ago
10

a card is chosen at random from a deck of 52 cards it is then replaced and a second card is chosen what is the probability of ge

tting a jack and then an eight
Mathematics
2 answers:
castortr0y [4]3 years ago
6 0
There are 4 jacks and 4 eights so with replacement:

P(Jand8)=(1/13)^2=1/169
Pachacha [2.7K]3 years ago
4 0
Their are 4 Jacks in a set of 52 cards so the probability to get a jack = 4/52=1/13 same for the eights

The cards was replaced then the total number of card is still 52. Now after selecting a Jack, you want to select an eight.

This is a conditional probability select a jack AND select an eight
P(Jack AND eight) = 1/13 x 1/13 - 1/169 = 0.006 or 0.6%
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Step-by-step explanation:


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Step-by-step explanation:

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Grace [21]
<h3>Given :-</h3>

\\

  • x=y-1
  • x+2y=8

\\

<h3>To find:</h3>

\\

  • Value of x
  • Value of y

\\

<h3>Solution:-</h3>

Let say it is first equation:-

x=y-1. . . . (1)

and this is second equation:-

x+2y=8 . . . . (2)

\\  \\

Simplifying 1 equation:-

  • x = y - 1
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  • y = x + 1

Put this value of y in second equation.

\\

\dashrightarrow \sf \: x+2y=8

\\

\dashrightarrow \sf \: x+2(x + 1)=8

\\

\dashrightarrow \sf \: x+2x +2=8

\\  \\

\dashrightarrow \sf \: 3x +2=8

\\  \\

\dashrightarrow \sf \: 3x=8 - 2

\\  \\

\dashrightarrow \sf \: 3x=6

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\dashrightarrow \sf \: x=6 \div 3

\\  \\

\dashrightarrow \sf \: x= \bf2

\\

to find value of y :-

y = x + 1

y = 2 + 1

y = 3

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verification:-

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1 equation:-

x = y - 1

put value of x and y

2 = 3 - 1

2 = 2

LHS = RHS

Hence verified!

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2 equation:-

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  • x+2y=8

put value of x and y

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LHS = RHS

Hence verified!

\\

Both equation verified!

.°. value of x and y is 2 and 3 respectively

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