Take the area of the small photograph and divide it by four, assuming it's a square, each side would then be 6 inches. The large photograph has double the side length of the small one, so 6 multiplied by 2 is 12. To find the area of the large (square) photograph, multiply 12 by 12 as two of the sides, and the area of the large photo is 144 square inches
Answer:
Step-by-step explanation:
If the square has an area of 49 ft^2, then the length of one of its sides is
s = √(49 ft^2) = 7 ft, and its perimeter is P = 4(7 ft) = 28 ft.
As for the rectangle: let W and L represent the width and length, respectively. Then W*L = 24 ft^2 is the area. L = W + 2 ft. Therefore,
W(W + 2) = 24, or W^2 + 2W - 24 = 0, or (W +6)(W - 4) = 0. Thus, W = 4 ft.
The perimeter of this rectangle is P = 2W + 2L, or
P = 2(4 ft) + 2(6 ft) = 24 ft.
The square has the larger perimeter: It is 28 ft.
Answer:
um ok i do not know
Step-by-step explanation:
Answer:
b=7
Step-by-step explanation:
3-5b=-32
-5b=-32-3
-5b=-35
Divide both sides by -5
b=7
The answer should be 0.422
