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bearhunter [10]
3 years ago
5

If your percentile rank in a group of 500 students is 84, how many persons rank lower than you?

Mathematics
2 answers:
julsineya [31]3 years ago
5 0
If you do 84 x 5 then you have 420 people lower than you 
NeX [460]3 years ago
5 0
First find 84% of 500
---> 0.84*500 = 420

If you are person 420, then 419 rank lower.
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Quinn used compensation to find the product of 37x4. First, she found 40x4=160. Then she adjusted that product by adding 3 group
torisob [31]
<span>Quin is adding the compensation needed instead of subtracting. First she calculated 40x4. She is trying to find 37x4. To do this, she would have to instead gather all the data: 3x4 = 12 40x4 = 160 Subtract instead of add: 40x4 - 3x4 = ? 160 - 12 = 148 The answer is 148.</span>
7 0
3 years ago
8. Mr. Azu invested an amount at rate of 12% per annum and invested another amount, GH¢
sashaice [31]

Answer:

GH¢. 18098.46

Step-by-step explanation:

Let the first investment giving 12% interest per annum be Bank A

Let the 2nd investment giving 10% per annum be bank B

Let the first amount invested be

GH¢. X and let the second amount invested be GH¢. X + 580

Thus; In bank A;

Principal amount in first = GH¢. x

rate = 12 %

time = 1 year

Formula for simple interest = PRT/100

Where P is principal, R is rate and T is time.

So, interest in his investment = 12X/100 = 0.12X

while in bank B;

principal amount = GH¢. X + 580

rate = 14%

time = 1 yr

So, interest in his investment = [(X + 580) × 14]/100

= 0.14(X + 580)

So, total accumulated interest is;

0.12X + 0.14(X + 580) = 0.12X + 0.14X + 81.2 = 0.26X + 81.2

Now, we are given accumulated interest = GH¢. 2,358.60

Thus;

2358.60 = (0.26X + 81.2)

2358.6 - 81.2 = 0.26X

X = 2277.4/0.26

X = 8759.23

So,

first amount invested = GH¢. 8759.23

Second amount invested = GH¢. 8759.23 + GH¢. 580 = GH¢. 9339.23

Total amount invested = GH¢. 8759.23 + GH¢. 9339.23 = GH¢. 18098.46

4 0
3 years ago
Seven times a sum of a number and 1 is 63
kompoz [17]
7(x+1)=63
7 times a number(x) +1 
7 0
3 years ago
Read 2 more answers
In 20 years,
Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

i honesty dont know if so i would help

8 0
3 years ago
Find two consecutive positive even integers such that the square of the first decreased by 64 equals 3 times the second.
IRINA_888 [86]

Answer:

10 and 12

Step-by-step explanation:

let the consecutive even integers be n and n + 2 , then

n² - 64 = 3(n + 2) ← distribute parenthesis

n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )

n² - 3n - 70 = 0 ← in standard form

(n - 10)(n + 7) = 0 ← in factored form

Equate each factor to zero and solve for n

n - 10 = 0 ⇒ n = 10

n + 7 = 0 ⇒ n = - 7

Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12

The 2 numbers are 10 and 12

8 0
3 years ago
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