Question

A coach throws a football from a height of 4 feet with an initial velocity of 59 feet per second at an elevation angle of 45 degrees. Which parametric equation represents the path of the football

Answer 1

Answer:

$x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2$

Step-by-step explanation:

From the question we are told that

Height $h=4feet$

Initial velocity of$v_0=59 feet/sec$

Angle $\theta= 40\textdegree$

Generally the parametric equation for projectile motion is mathematically given by

$x=(v_0cos\theta)t,y=y_0+(v_0sin\theta)t-16t^2$

Therefore

$x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2$

The parametric equation that represents the path of the football

$x=(59cos 45\textdegree)t,y=4+(v_0sin45\textdegree)t-16t^2$

Answer 2

Answer:

C

Step-by-step explanation: