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3 years ago

What is the common interest of $628 5% and 4 months?

Mathematics

1 answer:

ch4aika [34]3 years ago

4 0

$i = prt$
$i = 628 \times .05 \times 4$
$i = 31.40 \times 4 = 125.60$

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A) Find the average rate of change of the area of a circle with respect to its radius r as r changes from 4 to each of the follo

nata0808 [166]

So the question wants to calculate the change of the area among the circles in respect to its radius changes and the best answer would be the following:
A. 50.27 to 78.54
B.50.27 to 63.62
C.50.27 to 52. 81

The rate of change are the following:
A. 56.24%
B. 26.56%
C. 5.05%

7 0

3 years ago

Read 2 more answers

Work out the value of x.

tangare [24]

Answer:

The value of x could be anything, so I don't know what you mean until you have some sort of equation or graph - or anything at that.

Step-by-step explanation:

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3 years ago

What is the interquartile range (IQR) of the following data set?

OleMash [197]

Answer:

Step-by-step explanation:

Arrange data set

19, 4, 17, 3, 6, 5,5, 3, 11, 12, 3, 7, 15, 8, 8, 10,5, 3, 12, 41, 36

in ascending order

3, 3, 3, 3, 4, 5, 5, 5, 6, 7, 8, 8, 10, 11, 12, 12, 15, 17, 19, 36, 41

The median is $Q_2=8$

$Q_1=\dfrac{4+5}{2}=4.5$

$Q_3=\dfrac{12+15}{2}=13.5$

Thus, the interquartile range is

$Q_3-Q_1=13.5-4.5=9$

4 0

3 years ago

The oven tray is 600mm by 500mm. A cake tin is 25cm in diameter. How many cake tins can jenny fit on the oven tray at one time?

vlada-n [284]

Area of Circle= $\pi 
$ $r^{2}$
= $\frac{22}{7}$ x $( \frac{25cm}{2}) ^{2}$
= 490.87 $cm^{2}$

Area of Oven tray= 60cm x 50cm
= 3000 $cm^{2}$

: . # tin that can hold on bake tray= 3000 $cm^{2}$ / 490.87 $cm^{2}$ = 6.11
Thus making it logically 6.....

8 0

3 years ago

3(2−4)=−30 step by step

Margarita [4]

3•2-3•4
6-12=-30
-6=-30
false

6 0

3 years ago