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4 years ago

The oven tray is 600mm by 500mm. A cake tin is 25cm in diameter. How many cake tins can jenny fit on the oven tray at one time?

1 answer:

8 0

Area of Circle= $\pi 
$ $r^{2}$
= $\frac{22}{7}$ x $( \frac{25cm}{2}) ^{2}$
= 490.87 $cm^{2}$

Area of Oven tray= 60cm x 50cm
= 3000 $cm^{2}$

: . # tin that can hold on bake tray= 3000 $cm^{2}$ / 490.87 $cm^{2}$ = 6.11
Thus making it logically 6.....

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Help me if you understand thanks sm

kumpel [21]

First, find the slope of the line using the formula for slope:

m = (y2 - y1) / (x2 - x1)

m = (4 - (-2)) / (-3 - 2) = -6/5

Then, use the point-slope formula using a point that you were given and the slope that you calculated.

y - y1 = m(x - x1)

y - 4 = (-6/5)(x + 3)

Then, simply get y alone.

y = (-6/5)x + 2/5

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2 years ago

PLEASE HELP ASAP 5 STARS, 20 POINTS

777dan777 [17]

Answer:

Step-by-step explanation:

Using the inequality rule, the third side has to be less than 12 + 16 = 28.
So, any answer of 28 or more than 28 does NOT satisfy the length.
It also has to be more than 4 to satisfy the inequality rule.

In short words, 4 < x < 28.

A, B and C all satisfy, because they are in the range of x

D) 32 is >28, so this is the wrong answer and CANNOT be the value of x.

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3 years ago

Read 2 more answers

Find the area for both. The TRIANGLE looking one is the first one!!

Rudiy27

The first one is b the second one is b too

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4 years ago

for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation

Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample proportion of defective items = 12,898

s = sample standard deviation = 7,719

n = sample size = 5

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.776 < $t_4$ < 2.776) = 0.95 {As the critical value of t at 4 degrees of

freedom are -2.776 & 2.776 with P = 2.5%}

P(-2.776 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.776) = 0.95

P( $-2.776 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,898-2.776 \times {\frac{7,719}{\sqrt{5} } }$ , $12,898+2.776 \times {\frac{7,719}{\sqrt{5} } }$ ]

= [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

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4 years ago

Which is the best prediction for the number of pages in a chapter that takes 18 minutes to read?

mario62 [17]

Answer with explanation:

Time taken by a person to read number of pages in a chapter= 18 minutes

It is not given what is the length of the page.So,we can't say exactly how many pages can a person read by completely understading what is written in each page in a chapter.

So, to fully understand each and every page in 18 minutes you can read minimum number of pages from the option given.

Option A:⇒ 15, is most appropriate.

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3 years ago

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