Question

Use continuity to evaluate the limit. lim x→16 20 + x 20 + x step 1 consider the intervals for which the numerator and the denominator are continuous. the numerator 20 + x is continuous on the interval the denominator 20 + x is continuous and nonzero on the interval

Answer 1

Answer:

$\lim_{x \to 16} \frac{20+x}{20+x}$ = 1

Step-by-step explanation:

We are given the expression, $\lim_{x \to 16} \frac{20+x}{20+x}$.

Since, we have that,

The numerator and denominator is (20+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to $(-\infty,\infty)$.

Thus, the limit exists and is given by,

$\lim_{x \to 16} \frac{20+x}{20+x}$ = $\frac{20+16}{20+16}$ = $\frac{36}{36}$ = 1.

So, $\lim_{x \to 16} \frac{20+x}{20+x}$ = 1.