Answer:
(y+2) = (1/3)(x-1)
Answer in point-slope form, you can rearrange this into the form which you need.
Step-by-step explanation:
recall that the general point-slope form of a linear equation looks like :
(y - y₁) = m(x - x₁)
where m is the slope and (x₁,y₁) is any point on the line
here we are given m = 1/3 and (x₁,y₁)=(1,-2)
simply substitute this info into the general equation above
(y - y₁) = m(x - x₁)
(y - (-2) ) = (1/3)(x - 1)
(y+2) = (1/3)(x-1) Answer in point-slope form, you can rearrange this into the form which you need.
Answer:
The answer is below
Step-by-step explanation:
Plotting the following constraints using the online geogebra graphing tool:
x + 3y ≤ 9 (1)
5x + 2y ≤ 20 (2)
x≥1 and y≥2 (3)
From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).
We need to minimize the objective function C = 5x + 3y. Therefore:
At point A(1, 2): C = 5(1) + 3(2) = 11
At point B(1, 2.67): C = 5(1) + 3(2.67) = 13
At point C(3, 2): C = 5(3) + 3(2) = 21
Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.
Something u need to do dude
The two values are positive 9 and negative 9
1 2 3
1 2 3 1 2 3 1 2 3
123 123 123 123 123 123 123 123 123
3 3 3 3 3 3 3 3 3
3(9)
27