Question

W 31/5 yds L 12 yds what is the area of a rectangle?

Answer 1

Remember that the equation for the area of a rectangle is A = LW, where A=are of the rectangle, L=length of the rectangle and W=width of the rectangle.

You're given that L = 12yds and W = $\frac{31}{5}$ yds. Plug these values into your equation for the area of a rectangle and solve for A:
$A = LW\\ A = (12\:yds)(\frac{31}{5}\:yds)\\ A = \frac{12 \times 31}{5} \: yds^{2} \\ A = 74.4 \: yds^{2}$

The area of the rectangle is 74.4 $yds^{2}$.