Y=mx +b plug that in , so the 23.95 would be the flat fee then you add 0.32
250 =23.95+0.32 subtract from both sides then divide the answer is 10 miles
Answer:
Step-by-step explanation:
Given : There are six balls in bag
Basketballs=2
Playground balls =3
Soccer ball =1
To Find : the probability that if you pick one of the balls without looking, it will be a soccer ball
Solution :
Total no. of balls = 6
No. of soccer balls = 1
Probability = favorable outcomes / total outcomes
Since total outcomes = total no. of balls =6
And favorable outcome = no. of soccer balls = 1
Thus , Probability of getting soccer ball = 
Hence the probability that if you pick one of the balls without looking, it will be a soccer ball:
ANSWER
X < 9
Solve
2x < - x + 20 + 7
2x < - x + 27 change the signs
2x + x < 27 add the like terms
3x < 27 divide by 3
x < 9
Answer:
72 dollars I believe
Step-by-step explanation:
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
