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Viefleur [7K]
3 years ago
8

How do I set this up?

Mathematics
1 answer:
Sholpan [36]3 years ago
5 0

I am pretty sure you set this equation up correctly. All you need to do is calculate the approximate value, which is -2.91256.

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The sum of 5 and the twice a number is at most 27
melamori03 [73]

Answer:

Step-by-step explanation:

let the number=x

5+2x≤27

2x≤25-5

2x≤20

x≤4

6 0
3 years ago
Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

Hence\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx = \dfrac{1}{40(1-2x^5)^4} +C

5 0
3 years ago
Sin(-x)= -cos x for all values of x. True or false
kogti [31]

Answer:

That's incorrect. The simplest way to show this is by evaluating the functions at a given point. Let's say x=0, then:

Sin(-x) = Sin(0) = 0

-cos x = -cos (0) = -1

Therefore, Sin(-x)≠-cos x.

5 0
3 years ago
Read 2 more answers
Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1
Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in \frac{1}{1.5} minutes

Hence

10.50 mph will be increased in \frac{1}{1.5} \times 10.50 minutes

= \frac{10.5}{1.5}

=7

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0
3 years ago
The jars of paint in the art room have different amounts of paint. The green paint jar is 4/8 full. The purple paint jar is 4/6f
natulia [17]
4/8 is less full because it's only half compared to 4/6 which is 1.5
7 0
3 years ago
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