Answer:
Step-by-step explanation:
Since the number of pages that this new toner can print is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the number of pages.
µ = mean
σ = standard deviation
From the information given,
µ = 2300 pages
σ = 150 pages
1)
the probability that this toner can print more than 2100 pages is expressed as
P(x > 2100) = 1 - P(x ≤ 2100)
For x = 2100,
z = (2100 - 2300)/150 = - 1.33
Looking at the normal distribution table, the probability corresponding to the z score is 0.092
P(x > 2100) = 1 - 0.092 = 0.908
2) P(x < 2200)
z = (x - µ)/σ/√n
n = 10
z = (2200 - 2300)/150/√10
z = - 100/47.43 = - 2.12
Looking at the normal distribution table, the probability corresponding to the z score is 0.017
P(x < 2200) = 0.017
3) for underperforming toners, the z score corresponding to the probability value of 3%(0.03) is
- 1.88
Therefore,
- 1.88 = (x - 2300)/150
150 × - 1.88 = x - 2300
- 288 = x - 2300
x = - 288 + 2300
x = 2018
The threshold should be
x < 2018 pages
Step-by-step explanation:
Hope this is correct and helpful
HAVE A GOOD DAY!
Y-4X =3 ; 2x-3y=21
Y= 3+ 4x
2x -3( 3+4x)= 21
2x- 9- 12x= 21
-10x -9= 21
-10x -9+9= 21+9
-10x = 30
X= 30/-10= -3
Y= 3+4x = 3+ 4* (-3)= 3-12= -9
The correct answer is 12:16 P.M.
<h3>How to find when did Deb finish eating lunch ?</h3>
According to the problem,
- Deb started doing yard work at 9:52 A.M.
- After working for 1 hour and 48 minutes, she stopped to have lunch.
- It took her 36 minutes to eat lunch.
∴ Time at which Dev finishes her lunch =
9:52 A.M. + ( 1 hour and 48 minutes + 36 minutes )
= 11:40 A.M. + 36 minutes = 12 : 16 P.M.
∴ Deb finish eating lunch at 12:16 P.M.
Find out more information about time calculations here: brainly.com/question/1933707
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