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insens350 [35]
3 years ago
10

I don't get these what Do I do

Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0

Answer:

No idea

Step-by-step explanation:

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What is an equation in pointelope form for the line that passes through the points (4. – 1) and (-3,0)
bulgar [2K]

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1/3

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2nd one

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3 years ago
ONCE I HIT 30 ILL GIVE YOU 100 Points if i get a good grade Maybe even more
N76 [4]

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The correct anwser is 2x+5<4

Step-by-step explanation:

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3 years ago
The volume of a cube is 96 cubic millimeters. What is the length of each edge of the cube?
steposvetlana [31]

Answer:

V= a³ => 96 = a³ => a= ∛96 =2∛12

The length of each edge of the cube : C : 2∛12

Step-by-step explanation:

5 0
3 years ago
Maura can buy daffodil bulbs in packages of 3 for $5.37 or in packages of 2 for $4.52. How much money does she save by buying 30
fredd [130]

Answer:

  $14.10

Step-by-step explanation:

To have 30 bulbs, Maura can buy 10 packages of 3 at $5.37 each, for a total of $53.70. Or, she can buy 15 packages of 2 at $4.52 each, for a total of $67.80.

Buying in packages of 3, Maura saves $67.80 -53.70 = $14.10.

7 0
3 years ago
Determine whether or not f is a conservative vector field. If it is, find a function f such that f = ∇f. (if the vector field is
Likurg_2 [28]

A function assigns the values. The function f = xy²-2x² satisfies a conservative vector field F = ∇f.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

Given F(x,y) = (y² - 4x) i + 2xy j, and it is needed to be known that,

f_x(x,y)=y^2-4x\\f_y(x,y) = 2xy

Let's look for a primitive of y²-4x with regard to x. Because we regard y (and y²) as constants, a primitive of y² is xy², just as a primitive of k is xk (because we treat y² as a constant). Because a primitive of x equals x²/2, a primitive of 4x is 2x². As a result, a primitive of y²-4x is xy²-2x². We can get any other primitive by adding constants, but because we considered y as a constant, we have that.

f(x,y) = xy²-2x²+c(y)

where c(y) only depends on y (thus, it is constant respect with x).

To learn more about c(y), we shall deduce the formula in terms of y.

2xy=f_y(x,y)

      =\dfrac{d}{dy}(xy^2-2x^2+c(y))\\\\=2xy-0+\dfrac{d}{dy}c(y)\\\\=2xy+\dfrac{d}{dy}c(y)

Thus, d/dy is constant. We can take f(x,y)=xy²-2x². This function f satisfies that  F = ∇f.

Learn more about Function:

brainly.com/question/5245372

#SPJ4

3 0
2 years ago
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