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2 years ago

What sum would yield an interest of 36$ in 3 years at 3%p.a.

1 answer:

7 0

Amount of Interest = $36
Rate of interest = 3% per annum
Total time period for which the money was invested = 3 years
Let us assume the Principal amount = x
Then
Interest = Principal * Rate of Interest * time
36 = x * 3% * 3
36 = 9x/100
36 * 100 = 9x
3600 = 9x
x = 3600/9
= 400
So the initial sum of the money that was invested was $400.

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Find a rectangular equation. X = 3tan t, Y = 2sec t, for in (−π /2 , π /2 )

anzhelika [568]

Answer:

Step-by-step explanation:

$x= 3tan(t) \rightarrow tan(t) = \frac{x}{3} \rightarrow tan^2(t) = \frac{x^2}{9}$

$y= 2sec(t) \rightarrow sec(t) = \frac{y}{2} \rightarrow sec^2(t) = \frac{y^2}{4}$

$sec^2(t) -tan^2(t) =1$

$\frac{y^2}{4} -\frac{x^2}{9} =1$

is the rectangular equation of the parameter functions.

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3 years ago

Jennifer travels from Boston , Massachusetts, to Fairfield, Connecticut, a distance of 90 miles, at a speed of 45 miles per hour

Natali5045456 [20]

Answer: 52 1/2

Step-by-step explanation: I just found the average of the numbers.

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2 years ago

A television game show has 11 doors, of which the contestant must pick 3. Behind 3 of the doors are expensive cars, and behind

bezimeni [28]

For there to be 1 car, we consider two possible outcomes:

The first door opened has a car or the second door opened has a car.

P(1 car) = 2/6 x 4/5 + 4/6 x 2/5

P(1 car) = 8/15

For there to be no car in either door

P(no car) = 4/6 x 3/5

P(no car) = 2/5

Probability of at least one car is the sum of the probability of one car and probability of two cars:

P(2 cars) = 2/6 x 1/5

= 1/15

P(1 car) + P(2 cars) = 8/15 + 1/15

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3 years ago

Simplify<br> 3x^2+ 13x – 10<br> 9x^2 - 4

svetlana [45]

Answer:

The top one is (3x−2)(x+5)

the bottom one is (3x−2)(3x+2)

Step-by-step explanation:

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2 years ago

10. simplify the rational expression by rationalizing the denominator.( 1 point ) 4√150/√189x

ddd [48]

Rationalizing the denominator, simply means "getting rid of that pesky root at the bottom", and we do so by simply multiplying it by something to take it out, of course, we multiply the bottom, we have to also multiply the top,

$\bf \cfrac{4\sqrt{150}}{\sqrt{189x}}\cdot \cfrac{\sqrt{189x}}{\sqrt{189x}}\implies \cfrac{4\sqrt{150}\sqrt{189x}}{(\sqrt{189x})^2}\implies \cfrac{4\sqrt{(150)({189x})}}{189x}$

$\bf \cfrac{4\sqrt{28350x}}{189x}\qquad 
\begin{cases}
28350=2\cdot 3\cdot 3\cdot 3\cdot 3\cdot 5\cdot 5\cdot 7\\
\qquad 2\cdot 3^2\cdot 3^2\cdot 5^2\cdot 7\\
\qquad 2\cdot (3^2)^2\cdot 5^2\cdot 7\\
\qquad 2\cdot (3^2\cdot 5)^2\cdot 7\\
\qquad 2\cdot (45)^2\cdot 7\\
\qquad 14\cdot 45^2
\end{cases}\implies \cfrac{4\sqrt{14\cdot 45^2}}{189x}
\\\\\\
\cfrac{4\cdot 45\sqrt{14}}{189}\implies \cfrac{180\sqrt{14}}{189x}\implies \cfrac{20\sqrt{14}}{21x}$

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3 years ago