2 years ago

The radius of a circle is 4 kilometers. What is the circumference?

Mathematics

1 answer:

zaharov [31]2 years ago

3 0

Answer:

25.12 kilometers

Step-by-step explanation:

$c = 2\pi \: r$

C = 2 × 3.14 × 4

C = 25.12

You might be interested in

Write in ordinary form<br> 8.14 x 10-8

amid [387]

Answer:

Hello!

______________________

8.14*10=81.4 Is correct

Step-by-step explanation: Multiply 10 by 8.14.

Hope this helped you!

8 0

3 years ago

it is 3452 feet round trip from craig's house to his school. if he went to school 79 times this year, how many feet did he trave

Setler [38]

3531 you have to add them all

7 0

2 years ago

Read 2 more answers

Find an explicit formula for the arithmetic sequence -5,13,31,49,...

nadezda [96]

Step-by-step explanation:

b(n) = b(1) + (n-1) d, where d is the difference,

d = 13-(-5) = 18

b(n) = (-5) + (n-1)(18)

= -5 +18n -18

b(n) = 18n -23

6 0

2 years ago

A car drives 60 miles per hour. write and solve an equation to find the number of hours it takes the car to travel 360 miles

Flura [38]

360 - 60 is 6. So 6 times 60 = 360 which means it takes 6 hours to travel 360 miles.
60 * x = 360

6 0

2 years ago

Read 2 more answers

An animation has two scenes, each of them being one second long. In the first scene, an object moves along the path p⃗ 1(t)=(−8t

bagirrra123 [75]

Answer: $p_{2}(t)=(-8t^{2}+3t-5,7t^{2}+10,8t^{2}+6t+12)$

Step-by-step explanation: Velocity is the first derivative of position function, so:

$p'_{1}(t)=(-16t+3,14t,16t+6)$

Since in the second scene acceleration is zero, velocity must be constant, which means velocity in the second scene is the same as in the first scene, i.e.,

$p'_{2}(t)=p'_{1}(t)$

$p'_{2}(t) = (-16t+3,14t,16t+6)$

To determine position function, integrate it:

$p_{2}(t) = \int\limits {(-16t+3,14t,16t+6)} \, dt$

$p_{2}(t) = (-8t^{2}+3t+c_{1},7t^{2}+c_{2},8t^{2}+6t+c_{3})$

Now, the "initial condition" is that

$p_{2}(0)=p_{1}(1)$

$p_{2}(0) = (c_{1}c_{2},c_{3})$

$p_{1}(1)=(-8.1^{2}+3.1,7.1^{2}+3,8.1^{2}+6.1-2)$

$(c_{1},c_{2},c_{3})=(-5,10,12)$

$p_{2}(t)=(-8t^{2}+3t-5,7t^{2}+10,8t^{2}+6t+12)$

<u>Position function in the second scene is </u> $p_{2}(t)=(-8t^{2}+3t-5,7t^{2}+10,8t^{2}+6t+12)$ <u />

8 0

2 years ago