<em><u>Question:</u></em>
A local hamburger shop sold a combined total of 695 hamburgers and cheeseburgers on Sunday. There were 55 fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Sunday?
<em><u>Answer:</u></em>
375 hamburgers and 320 cheese burgers were sold
<em><u>Solution:</u></em>
Let "a" be the number of hamburgers sold
Let "b" be the number of cheese burgers sold
<em><u>Local hamburger shop sold a combined total of 695 hamburgers and cheeseburgers on Sunday</u></em>
Therefore,
a + b = 695 ------------ eqn 1
<em><u>There were 55 fewer cheeseburgers sold than hamburgers</u></em>
Number of cheese burgers sold = number of hamburgers - 55
b = a - 55 --------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
a + a - 55 = 695
2a = 695 + 55
2a = 750
a = 375
<em><u>Substitute a = 375 in eqn 2</u></em>
b = 375 - 55
b = 320
Thus 375 hamburgers and 320 cheese burgers were sold
