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Zinaida [17]
3 years ago
11

A local hamburger shop sold a combined total of 695 hamburgers and cheeseburgers on Sunday. There were 55 fewer cheeseburgers so

ld than hamburgers.
Mathematics
1 answer:
rjkz [21]3 years ago
8 0

<em><u>Question:</u></em>

A local hamburger shop sold a combined total of 695 hamburgers and cheeseburgers on Sunday. There were 55 fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Sunday?

<em><u>Answer:</u></em>

375 hamburgers and 320 cheese burgers were sold

<em><u>Solution:</u></em>

Let "a" be the number of hamburgers sold

Let "b" be the number of cheese burgers sold

<em><u>Local hamburger shop sold a combined total of 695 hamburgers and cheeseburgers on Sunday</u></em>

Therefore,

a + b = 695 ------------ eqn 1

<em><u>There were 55 fewer cheeseburgers sold than hamburgers</u></em>

Number of cheese burgers sold = number of hamburgers - 55

b = a - 55 --------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 2 in eqn 1</u></em>

a + a - 55 = 695

2a = 695 + 55

2a = 750

a = 375

<em><u>Substitute a = 375 in eqn 2</u></em>

b = 375 - 55

b = 320

Thus 375 hamburgers and 320 cheese burgers were sold

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