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dexar [7]
3 years ago
13

Which polynomials are prime? Check all that apply.

Mathematics
2 answers:
Katen [24]3 years ago
8 0

Answer:

a b d

Step-by-step explanation:

is all that apply

cupoosta [38]3 years ago
3 0

Answer:a c e

Step-by-step explanation:just took it. Those are all that apply.

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Ipatiy [6.2K]
Great
I really like this question, cause, you know, there isn't one. But good for Erik and Nita.
5 0
4 years ago
Combine these unlike fractions, then simplify. 2 2/3 + 2 7/12 need answer asap plz explain
slega [8]

Answer: 5 1/4

Step-by-step explanation:

8/3 + 2 7/12

8/3 + 31/12

= 21/4

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3 0
3 years ago
Match the trinomials with their factors. Tiles a2 + a − 20 a2 − 9a + 20 a2 − 8a − 20 a2 − 12a + 20 a2 − 19a − 20 Pairs Factors T
chubhunter [2.5K]
For this case we have to factorize the following trinomials as the product of two binomials.
 We have then:
 a2 + a - 20
 (a + 5) (a-4)

 a2 - 9a + 20
 (a-5) (a-4)

 a2 - 8a - 20
 (a-10) (a + 2)

 a2 - 12a + 20
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 a2 - 19a - 20
 (a-20) (a + 1)
3 0
4 years ago
PLEASE HELP ME NOW!!
puteri [66]

Answer:

x=4+-2\sqrt{7}

Step-by-step explanation:

To solve, we need to take square root of both sides first:

(x-4)^2=28\\\sqrt{(x-4)^2} =+-\sqrt{28} \\x-4=+-\sqrt{28}

Now we use the property of radical shown below to simplify square root of 28:

Property:  \sqrt{x*y}=\sqrt{x} \sqrt{y}

Now, we have:

x-4=+-\sqrt{28}\\x-4=+-\sqrt{4*7}\\x-4=+-\sqrt{4}\sqrt{7}\\x-4=+-2\sqrt{7}

Now we take 4 to the other side and isolate x:

x-4=+-2\sqrt{7} \\x=4+-2\sqrt{7}

first answer choice is right.

4 0
4 years ago
Read 2 more answers
Please help ASAP 1-6
stealth61 [152]
Add your decimals to get the answer.
7 0
3 years ago
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