Answer:
Explanation:For the first given equation, we will need to isolate the x². This can be done as follows:
x² + y² = 25
x² + y² - y² = 25 - y²
x² = 25 - y² ..................> I
For the second given equation:We will remove every x² and substitute with its equivalence from I as follows:
![\frac{x^2}{16} + \frac{y^2}{9} = 1](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%5E2%7D%7B16%7D%20%2B%20%20%5Cfrac%7By%5E2%7D%7B9%7D%20%3D%201)
![\frac{25-y^2}{16} + \frac{y^2}{9} = 1](https://tex.z-dn.net/?f=%20%5Cfrac%7B25-y%5E2%7D%7B16%7D%20%2B%20%20%5Cfrac%7By%5E2%7D%7B9%7D%20%3D%201)
Hope this helps :)
||cu|| = |c| * |u| = c[ magnitude of vector sum of 5i + 12j ] = 3sqrt(5^2 + 12^2)
= 3sqrt(169) = 3(13) = 39 (answer)
The slope of y=3 is 0! It's a horizontal line! Hope this clears things up :)
So the deviation was 2.5 grams
that means that the average/mean could have been
255-2.5 or 255+2.5 = 252.5 or 257.5
so if all of them weighed the same, none of them weighed less than 250 so the answer is 0%
Answer:
224
Step-by-step explanation:
<u>Base:</u>
A = Bh
A = 8(8) = 64
<u>Sides:</u>
A = 1/2 Bh
A = 1/2 8(10)
A = 40
<u>Then you do 40(4) because there are 4 sides:</u>
40 (4) = 160
<u>Then you add up the base and the sides:</u>
160 + 64 = 224
(I think this is the right answer)