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Gala2k [10]
3 years ago
7

Pls asap thank you guys very much

Mathematics
2 answers:
umka2103 [35]3 years ago
6 0
Yep the answer is B!!!
Pavel [41]3 years ago
3 0

Answer:

-11

Step-by-step explanation:

B

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Help I’ll give brain crown
ankoles [38]

Answer:

13. c

14.a

15.c

16.d

17.b

18.d

19.a

20.b

Step-by-step explanation:

7 0
3 years ago
What is the length of BC?<br><br> 18<br> 24<br> 20<br> 22
Alexeev081 [22]

Answer:

22

Step-by-step explanation:

it shows in the image that AC and AB are isosceles so 2x - 24 would be equal to x - 2

2x - 24 = x -2 ➡ x = 22

4 0
3 years ago
Read 2 more answers
Help pleaseee!!!!!!!!!!
katrin2010 [14]
It is b, I’m a teacher and I have taught my students that.
7 0
3 years ago
Read 2 more answers
Part D
Readme [11.4K]

Answer:

The equation for the profit made on the car wash is y = 5x – 75. Here, y is the profit made and x is the number of cars washed. So if the team washes 0 cars, x will be 0.

y = 5(0) – 75

y = -75

The point that represents this is (0, -75). Here, the value of the y-coordinate of the point is -75. Since it has a negative sign, it means that instead of making a profit, the team suffers a loss. So, if the baseball team washed no cars, it would lose $75.

Step-by-step explanation:

6 0
3 years ago
Suppose you have a bag containing 15 red beads, 12 white beads and 8 black beads. You are going to draw one bead out of the bag.
iren [92.7K]

Answer:

probability that you draw a black bead or a white bead that is P(E1 U E2)

= 20/35 = 0.571

Step-by-step explanation:

Given a bag containing 15 red beads, 12 white beads and 8 black beads

n(S) = 15 + 12 +8 = 35

Let 'E1 be the event of selecting black beads and E2 be the event of selecting white beads

n(E1) = 8 and n(E2) = 12

Probability of draw a black bead P( E1 ) = \frac{n(E_{1} )}{n(S)}

                                                      P(E_{1}) = \frac{8}{35}

Probability of draw a white bead P( E2 ) = \frac{n(E_{2} )}{n(S)}

                                                    P(E_{2}) = \frac{12}{35}

probability that you draw a black bead or a white bead that is P(E1 U E2)

and E1 n E2 = ∅ (disjoint events)

<u>Axiom of union </u>

<u></u>P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - P(E_{1}nE_{2})\\<u></u>

E1 n E2 = ∅ ⇒ P(E1 n E2) = p(∅) = 0

P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - 0

P(E_{1}UE_{2} ) = \frac{8}{35} +\frac{12}{35}

P(E_{1}UE_{2} ) = \frac{20}{35}

P(E_{1}UE_{2} ) = 0.571

8 0
4 years ago
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