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N76 [4]
3 years ago
15

Vladimir buys 1.20 pounds of Skittles, 312 pounds of M&Ms, and 5.2 pounds of pretzels. If the candy cost $1.20 a pound and t

he pretzels cost $1.10 a pound, how much did Vladimir spend?
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
6 0

Answer: $10.90

Step-by-step explanation:

Skittles-1.44

M&M's-3.744

Pretzels-5.72

Not sure if its a typo, thats if theres 3.12lbs of of M&M's

The answer is theres 312 M&M's is 374.4

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Which of the following is the equation for the line perpendicular to the line y= -x + 20 that passes through the point (-4, 2)?
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Answer:

Step-by-step explanation:

A 10= 4 plus 6

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2 years ago
Determine the equation of the inverse of y=1/4x^3-2
dedylja [7]

<u>Answer</u>


y⁻¹ = ∛(4x+8)



<u>Explanation</u>

y=(1/4)x³ - 2.

To find the inverse of this equation, you first make x the subject of the formular.

y=(1/4)x³ - 2

Multiply both sides by 4;

4y = x³ - 8

Add 8 on both sides of the equation;

4y + 8 = x³

x³ = 4y + 8

Apply the cube root on both sides to get the value of x;

x = ∛(4y+8)


The inverse of y=(1/4)x³ - 2 is;

y⁻¹ = ∛(4x+8)


7 0
3 years ago
Raphael dives a standard-sized dump truck. The dimensions of the bed of the truck are length 25 feet,width 8 feet , and height 6
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25×8×6
1200 square feet
4 0
2 years ago
Read 2 more answers
32 ÷ 24 is EXACTLY equal to A) 1.3 B) 2.7 C) 4 3 D) 8 3
Gre4nikov [31]
A)1.33333333333333333333333333333333333333333 Repeating

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3 years ago
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1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
3 years ago
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