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Ainat [17]
3 years ago
6

Mr. Sim invest $9000 at 1% per annum compound interest compounded daily. What is his amount at the end of the third day?

Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0

Answer:

The amount at the end of the third day is $9,000.74

Step-by-step explanation:

To calculate his amount, we shall be using the compound interest formula;

Mathematically;

A = I( 1 + r)^nt

where A is the amount which we want to calculate

I is the initial amount deposited = $9,000

r is the interest rate = 1% = 1/100 = 0.01

the daily interest will be 0.01/365 = 0.00002739726

nt is the number of times we shall be compounding = 3 times

Substituting these values;

A = 9,000(1 + 0.00002739726)^3

A = 9,000(1.00002739726)^3

A = 9,000.73974628665

which is approximately; 9,000.74

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The figure shows the relationship between the number of miles per gallon on the highway and that in the city for some cars.
Leno4ka [110]

In this relationship between the number of miles per gallon on the highway and that in the city for some cars are:

For each additional city mpg, the highway value goes up by

0.9478 mpg.

And It is inappropriate to interpret the intercept because no cars get 0 mpg in the city.

According to the statement

we have given that the relationship between the number of miles per gallon on the highway in the graphical representation and that in the city for some cars.

And we have to give some reasons for the given statements.

So, For this purpose, we know that the

A. In this statement we have to tell that the what is shown in the given relationship in the graph.

So, For each additional city mpg, the highway value goes up by

0.9478 mpg.

And the second statement is

B. I this we have to tell the intercept of the plane in the given Relationship.

So, It is inappropriate to interpret the intercept because no cars get 0 mpg in the city.

So, In this relationship between the number of miles per gallon on the highway and that in the city for some cars are:

For each additional city mpg, the highway value goes up by

0.9478 mpg.

And It is inappropriate to interpret the intercept because no cars get 0 mpg in the city.

Learn more about graph here

brainly.com/question/4025726

Disclaimer: This question was incomplete. Pleas find the full content below.

Question:

The figure shows the relationship between the number of miles per gallon on the highway and that in the city for some cars.

a. Report the slope and explain what it means.

b. Either interpret the intercept​ (7.792) or explain why it is not appropriate to interpret the intercept.

#SPJ4

8 0
2 years ago
A coin is flipped 10 times where each flip comes up either heads or tails. How many possible outcomes (a) contain exactly two he
Tems11 [23]

Answer:

a. 45

b. 176

c. 252

Step-by-step explanation:

First take into account the concept of combination and permutation:

In the permutation the order is important and it is signed as follows:

P (n, r) = n! / (n - r)!

In the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

Now, to start with part a, which corresponds to a combination because the order here is not important. Thus

 n = 10

r = 2

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

There are 45 possible scenarios.

Part b, would also be a combination, defined as follows

n = 10

r <= 3

Therefore, several cases must be made:

C (10, 0) = 10! / 0! * (10-0)! = 10! / (0! * 10!) = 1

C (10, 1) = 10! / 1! * (10-1)! = 10! / (1! * 9!) = 10

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

C (10, 3) = 10! / 3! * (10-3)! = 10! / (2! * 7!) = 120

The sum of all these scenarios would give us the number of possible total scenarios:

1 + 10 + 45 + 120 = 176 possible total scenarios.

part c, also corresponds to a combination, and to be equal it must be divided by two since the coin is thrown 10 times, it would be 10/2 = 5, that is our r = 5

Knowing this, the combination formula is applied:

C (10, 5) = 10! / 5! * (10-5)! = 10! / (2! * 5!) = 252

252 possible scenarios to be the same amount of heads and tails.

6 0
3 years ago
Elliot uses 3/8 pound of clay to make a charm for a necklace. how much clay does he use to make 4 charms?
Lapatulllka [165]

Answer:

3/2 pound of clay is used

5 0
3 years ago
Read 2 more answers
What is the value of x?<br> Enter<br> your answer in the box.<br> X=
Naddika [18.5K]

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try!

8 0
3 years ago
Suppose a, b denotes of the quadratic polynomial x² + 20x - 2022 &amp; c, d are roots of x² - 20x + 2022 then the value of ac(a
Alja [10]
<h3><u>Correct Question :- </u></h3>

\sf\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0 \: and \:  \\  \sf \: c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0 \: then \:

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) =

(a) 0

(b) 8000

(c) 8080

(d) 16000

\large\underline{\sf{Solution-}}

Given that

\red{\rm :\longmapsto\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0}

We know

\boxed{\red{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}

\rm \implies\:ab = \dfrac{ - 2020}{1}  =  - 2020

And

\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}

\rm \implies\:a + b = -  \dfrac{20}{1}  =  - 20

Also, given that

\red{\rm :\longmapsto\:c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0}

\rm \implies\:c + d = -  \dfrac{( - 20)}{1}  =  20

and

\rm \implies\:cd = \dfrac{2020}{1}  = 2020

Now, Consider

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)

\sf \:  =  {ca}^{2} -  {ac}^{2} +  {da}^{2} -  {ad}^{2} +  {cb}^{2} -  {bc}^{2} +  {db}^{2} -  {bd}^{2}

\sf \:  =  {a}^{2}(c + d) +  {b}^{2}(c + d) -  {c}^{2}(a + b) -  {d}^{2}(a + b)

\sf \:  = (c + d)( {a}^{2} +  {b}^{2}) - (a + b)( {c}^{2} +  {d}^{2})

\sf \:  = 20( {a}^{2} +  {b}^{2}) + 20( {c}^{2} +  {d}^{2})

\sf \:  = 20\bigg[ {a}^{2} +  {b}^{2} + {c}^{2} +  {d}^{2}\bigg]

We know,

\boxed{\tt{  { \alpha }^{2}  +  { \beta }^{2}  =  {( \alpha   + \beta) }^{2}  - 2 \alpha  \beta  \: }}

So, using this, we get

\sf \:  = 20\bigg[ {(a + b)}^{2} - 2ab +  {(c + d)}^{2} - 2cd\bigg]

\sf \:  = 20\bigg[ {( - 20)}^{2} +  2(2020) +  {(20)}^{2} - 2(2020)\bigg]

\sf \:  = 20\bigg[ 400 + 400\bigg]

\sf \:  = 20\bigg[ 800\bigg]

\sf \:  = 16000

Hence,

\boxed{\tt{ \sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) = 16000}}

<em>So, option (d) is correct.</em>

4 0
2 years ago
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