Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
Answer:
19,600
Step-by-step explanation:
0-49=50 numbers
n=50
r=3
C(n,r)=n!/(r!(n-r)!)
=50!/(47!)(3!)
C(n,r)=C(50,3)
=50!/(3!(50−3)!)
= 19600
Answer:
b. -2
Step-by-step explanation:
Note the slope-intercept form: y = mx + b
Note that:
y = (x , y)
m = slope
x = (x , y)
b = y-intercept
First, isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Subtract 2x from both sides of the equation:
2x (-2x) + y = (-2x) + 12
y = -2x + 12
Remember, m is the variable for the term that stands for the slope (directly next to the x variable). In this case, your answer will be -2
b. -2 is your answer.
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Step-by-step explanation:
<u>Initial value is the y-intercept:</u>
<u>Rate of change is the difference in the charge amount per year:</u>
- m = (1350 - 1200) / (8 - 5) = 150 / 3 = 50
<u>The equation would be:</u>
Answer:
507
Step-by-step explanation:
For the Algebraic Expression,
let the two numbers be X and y
lets assume x = 217
From the question,
217 + y = 724
y = 724-217
y = 507
Therefore, the other number is 507
