Answer:
30 gallons of 20% acid solution should be mixed.
Step-by-step explanation:
Let x gallons of a 20% acid solution was mixed with 30 gallons of a 40% solution, to obtain a mixture of 30% acid solution.
Therefore, final volume of the solution will be (x + 30) gallons.
Now concept to solve this question is
20%.(x) + 40%.(30) = 30%.(x + 30)
0.20(x) + 0.40(30) = 0.30(x + 30)
0.20x + 12 = 0.30x + 9
0.30x - 0.20x = 12 - 9
.10x = 3
x = 
x = 30 gallons
Therefore, 30 gallons of the 20% acid solution should be mixed.
Answer:
QN = 43
Step-by-step explanation:
3x-5 = 2x+8+3
3x-5 = 2x+11
x-5 = 11
x = 16
MP = 3x-5
MP = 3(16)-5
MP = 48-5
MP = 43
MP and QN are ≅ so QN = 43
Answer:
Step-by-step explanation:
MX = XN
5r² + 2r + 52 = 4r² + 12r + 27
5r² - 4r² + 2r - 12r + 52 - 27 = 0
r² - 10r + 25 = 0
(r - 5)² = 0
r - 5 = 0
r = 5
4r² + 12r + 27
4•5² + 12•5 + 27
4•25 + 60 + 27
100 + 60 + 27
187
The Second one
I hope I helped you.
I believe the answer is A. Undefined
Answer:
2325
Step-by-step explanation:
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