High school math classes are more advanced than middle school math classes
Alright
for a 45-45-90 triangle, if the legs are x then the hytponuse is x√2
so LM=x√2 is right
NM=x
also, tan=oposite side/adjacent side
so that would be LN/MN or MN/LN=x/x=1
so that would be tan(45)=1
so you want to check the 1st one, 3rd one and 5th one
NM=x
LM=x√2
tan(45°)=1 are the answers
Answer:
3
Step-by-step explanation:
3
Answer:
A customer who sends 78 messages per day would be at 99.38th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average of 48 texts per day with a standard deviation of 12.
This means that 
a. A customer who sends 78 messages per day would correspond to what percentile?
The percentile is the p-value of Z when X = 78. So



has a p-value of 0.9938.
0.9938*100% = 99.38%.
A customer who sends 78 messages per day would be at 99.38th percentile.