Answer:
1) The probability that the mean mpg for a random sample of 25 light vehicles is 0.042341.
2) between 20 and 25 --> 21-25/2.9 = -1.38
Step-by-step explanation:
Problem #1:
- Using the z-score formula, z = (x-μ)/σ/n, where x is the raw score = 20 mpg,μ is the population mean = 21 mpg , σ is the population standard deviation = 2.9, n = random number of samples.
<h3><u>X < 20</u></h3>
- = z = 20 - 21/2.9/√25
- = z = -1/2.9/5
- = z = -1.72414
<h2><u><em>Now</em></u></h2>
<em>P-value from Z-Table:</em>
<h3><u>P(x<20) = 0.042341</u></h3>
Problem #2:
<h3>21-25/2.9 = -1.38</h3>
Answer:
The answer is already 82.8
Step-by-step explanation:
The .8 is already to the tenth so it is 82.8
25n = t because its 25 beads per bag
2t<-4 divide both sides by 2
t<-2
...
7t>49 divide both sides by 7
t>7
So t=(-oo,-2) and t=(7,+oo)
t=(-oo,-2)U(7,+oo)
If you would like to know what percent of 75 is 33, you can calculate this using the following steps:
x% of 75 is 33
x% * 75 = 33
x/100 * 75 = 33 /*100/75
x = 33 * 100 / 75
x = 44%
Result: 44% of 75 is 33.