The genotypes would be bbTT X BbTt
Assuming that bark color is represented by B (b) allele and height is represented by T (t) allele.
Since the traits show simple dominance: blue (B) of dominant over purple (b) and tall (T) is dominant over short (t)
- The genotype of a tree that is purebred purple (bb) and tall (TT) would be bbTT
- The genotype of a tree that is heterozygous for both trait would be BbTt
- Thus, the cross would be bbTT x BbTt
More on genotypes can be found here: brainly.com/question/20730322?referrer=searchResults
Answer:
a Anaphase I
b Metaphase I
c Telophase I
d Anaphase II
e Prophase I
f Telophase II
Explanation:
Prophase I begins after the DNA has been duplicated, as shown in picture e. The chromosomes are condensed, and also visible, which is apparent in picture e.
The next stage is called Metaphase I, in which the pairs of homologous chromosomes align at The the centre of the cell and the spindle fibres attach, as shown in picture b.
The pairs of chromosomes are pulled apart to opposite poles of the cell by the spindle fibres., as shown in picture a. This stage is called Anaphase I.
Then, a process called Telophase I occurs, when the cell divides into two daughter cells. One of these cells is shown in picture c.
Picture d shows the stage Anaphase II, where the spindle has attached and the chromatids are pulled to the opposite poles of the cell.
The final picture left is picture f, which shows the daughter cell at the end of meiosis II, where the nuclear envelope is reforming, as in telophase II.
Answer: there is no gravity and no type of life on the moon therefore basically making it a huge target.
Explanation:
Answer:
So blood can reach the fetus
Explanation:
