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Sedaia [141]
4 years ago
8

The difference of Rick's height and 16 is 57. the variable r equals rick's height

Mathematics
2 answers:
anyanavicka [17]4 years ago
7 0
16 + r = 57 .
so ricks height is 48

irinina [24]4 years ago
3 0
First, the difference of Rick's height and 16 can be represented as r-16 because r represents Rick's height and difference means subtraction. When we set this equal to 57. we get r-16=57.

I hope this helps. 
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Which equation represents the line that is parallel to
GrogVix [38]

y=-5x-44

Step-by-step explanation:

5x+y=13 passes through (15,31)

rearrange the equation to y=mx+c

5x+y=13

y=-5x+13

substitute the points (15,31)

y=5x+c

31=5(15)+c

31=75+c

-44=c

y=-5x-44

Can be written as 5x+y=-44

8 0
3 years ago
If a and b can be replaced with any whole number in the equation a+ b=19. then there is?
Schach [20]

Answer:

C

Step-by-step explanation:

There isnt infinite because there is an answer of 19, and only so many whole numbers can add up to 19

There isnt 1 because 11+8 and 5+14 both equal 19

4 0
3 years ago
How to do division with arrays?
MariettaO [177]
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i believe this is the answer

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6 0
3 years ago
Select the correct answer from each drop-down menu.
kifflom [539]

Answer:

  1. 0.83
  2. 0.9
  3. steeper than
  4. slower than

Step-by-step explanation:

Letting t=1 in Ted's equation, we find that he climbs 5/6 stairs in 1 second. As a decimal, 5/6 ≈ 0.83.

Michael climbs 9 stairs in 10 seconds so his rate is ...

... (9 stairs)/(10 seconds) = (9/10) stairs/second = 0.9 stairs/second

Michael's graph will be a line with a slope of 0.9; Ted's graph will be a line with a slope of about 0.83, so the line on Michael's graph is steeper.

Ted climbs fewer stairs per second, so his rate is slower than Michael's.

_____

<em>Comment on the problem</em>

You're being asked to compare two different rates that are associated with two different people. First the comparison is one way, then it is the other way. This can be confusing. It might be helpful to draw and label a simple chart to help you keep it straight. (The attachment is such a chart scribbled on a bit of scratch paper. It is sufficient for the purpose.)

3 0
3 years ago
Let μ denote the true average tread life of a certain type of tire. consider testing h0: μ = 30,000 versus ha: μ &gt; 30,000 bas
san4es73 [151]
The probability of making a type II error is given by one minus the power of the hypothesis test.

In general for the alternative hypothesis , H_a:\mu\ \textgreater \ \mu_0

The power of a hypothesis test is given by:

\beta(\mu')=\phi\left(X \ \textless \  \mu_0+z_{1-\alpha}\frac{\sigma}{\sqrt{n}}|\mu'\right) \\  \\ =\phi\left(z_{1-\alpha}+\frac{\mu_0-\mu'}{\sigma/\sqrt{n}}\right) =\phi\left(z_{1-0.01}+\frac{30000-31000}{1500/\sqrt{16}}\right) \\  \\ =\phi\left(z_{0.99}+\frac{-1000}{1500/4}\right)=\phi\left(2.33-\frac{1000}{375}\right)=\phi(2.33-2.667) \\  \\\phi(-0.33)=0.3682

The probability of <span>making a type ii error when μ = 31,000 is given by

1-\beta(\mu')=1-0.3682 \\  \\ =0.6318</span>
6 0
3 years ago
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