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stealth61 [152]
3 years ago
9

Let μ denote the true average tread life of a certain type of tire. consider testing h0: μ = 30,000 versus ha: μ > 30,000 bas

ed on a sample of size n = 16 from a normal population distribution with σ = 1500. a test with α = 0.01 requires zα = z0.01 = 2.33. the probability of making a type ii error when μ = 31,000 is
Mathematics
1 answer:
san4es73 [151]3 years ago
6 0
The probability of making a type II error is given by one minus the power of the hypothesis test.

In general for the alternative hypothesis , H_a:\mu\ \textgreater \ \mu_0

The power of a hypothesis test is given by:

\beta(\mu')=\phi\left(X \ \textless \  \mu_0+z_{1-\alpha}\frac{\sigma}{\sqrt{n}}|\mu'\right) \\  \\ =\phi\left(z_{1-\alpha}+\frac{\mu_0-\mu'}{\sigma/\sqrt{n}}\right) =\phi\left(z_{1-0.01}+\frac{30000-31000}{1500/\sqrt{16}}\right) \\  \\ =\phi\left(z_{0.99}+\frac{-1000}{1500/4}\right)=\phi\left(2.33-\frac{1000}{375}\right)=\phi(2.33-2.667) \\  \\\phi(-0.33)=0.3682

The probability of <span>making a type ii error when μ = 31,000 is given by

1-\beta(\mu')=1-0.3682 \\  \\ =0.6318</span>
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Solve to find X. 1/5(x - 2) = 1/10 (x + 6)
LenaWriter [7]

Answer:

x = 10

Step-by-step explanation:

First, distribute:

\frac{1}{5} x - \frac{2}{5} =\frac{1}{10} x+\frac{6}{10}

Next, subtract \frac{1}{5}x from both sides:

-\frac{2}{5} = \frac{1}{10} x -\frac{1}{5} x+\frac{6}{10}

(multiply \frac{1}{5}x by 2 to get common denominator, \frac{2}{10} x )

-\frac{2}{5} =-\frac{1}{10}x +\frac{6}{10}

Next, subtract \frac{6}{10} from both sides:

-\frac{2}{5} -\frac{6}{10} =-\frac{1}{10} x

(multiply \frac{2}{5} by 2 to get common denominator, \frac{4}{10} )

-\frac{10}{10} =-\frac{1}{10} x ⇒ -1=-\frac{1}{10} x

Next, multiply both sides by 10:

-10=-x

FInally, divide both sides by -1:

x = 10

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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10 + 2(7 - 9x) = 5(2x - 12)<br><br><br>Full steps as well please
blagie [28]

Answer:

x = 3

Step-by-step explanation:

10 + 2(7 - 9x) = 5(2x - 12)

10 + 14 - 18x = 10x - 60

24 - 18x = 10x - 60

+60                 +60

-------------------------------------

84 - 18x = 10x

     +18x    +18x

-------------------------------------

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/28    /28

--------------------------------------

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3 years ago
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How do I solve this question?
Montano1993 [528]

Answer:

p = \frac{3}{2} , q = 9

Step-by-step explanation:

4x² + 12x ( factor out 4 from each term )

= 4(x² + 3x)

Using the method of completing the square

add/subtract ( half the coefficient of the x- term)² to x² + 3x

= 4(x² + 2(\frac{3}{2} )x + \frac{9}{4} - \frac{9}{4} )

= 4(x + \frac{3}{2} )² - 4 × \frac{9}{4}

= 4(x + \frac{3}{2} )² - 9

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