Answer:
-1 and 0
Step-by-step explanation:
X ^4+x = 0;
x*(x^3+1)=0;
x*[(x^3-x)+(x+1)]=0;
x*[x(x-1)(x+1)+(x+1)]=0;
x*(x+1)(x^2-x+1)=0;
Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0
x=0 or -1
1.61 is the correct answer
So the answer is, x1=-2, x2=9
x^2-7x=18
x^2-7x-18=0
x^2+2x-9x-18=0
x*(x+2)-9(x+2)=0
(x+2)*(x-9)=o
x+2=0
x-9=0
X=-2
X=9
I hope u understand!
The second one
Hope this helps :D
