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jonny [76]
3 years ago
7

Please help me pleaseeeeee easy multiple choice

Mathematics
1 answer:
zhenek [66]3 years ago
3 0
10. Correct answer is C.
11. C also
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3 hundred thousand 3 thousand 8 hundred 4 tens
alekssr [168]

Answer:

3384

Step-by-step explanation:

3 0
3 years ago
Express answer in exact form.
bazaltina [42]
The answer is 5.13 in²

Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
</span>
Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2            (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in

Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in

Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²

Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²

Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 =  5.13 in²
6 0
3 years ago
Read 2 more answers
PLEASE HELP!!
FromTheMoon [43]

Step-by-step explanation:

Given

Model to Actual = 5:9

5cm in Model = 9cm actual

1cm in model = (9/5)cm = 1.8cm

36cm in model = 1.8cm x 36 = 64.8cm

3 0
3 years ago
Todd and Joan each generate a random sample of the 250 students in Grade 7 at their school. Each sample has 20 students. Todd an
Sloan [31]

Answer:

B. There is a slightly more even distribution in the numbers in​ Joan's Group than in​ Todd's Group. C. Only one​ number, 28, is the same between the two samples.

Step-by-step explanation:Your welcome loves :)

8 0
3 years ago
HELP 20 POINTS!!!
Andrew [12]

The discriminant of equation ax^2+bx+c = 0 is b^2-4ac.

Here b = 12, a = -4, c = -9 so discriminatn is

b^2-4ac = 12^2-4(-4)(-9) = 144 - 144 = 0.

The discrimant is 0. This tells us that there is only 1 x-intercept for this quadratic

5 0
3 years ago
Read 2 more answers
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